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Alexus [3.1K]
3 years ago
8

4 ME FISHY BROTHERs :)

Mathematics
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

542.6

Step-by-step explanation:

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Can u pls help me with this question asap ​
serg [7]

Answer:

Either increase the number of acres that can be used for strawberry fields (by buying more land)..If we use the same numbers from earlier, then the farmer should use approximately 16.65 acres of land (or just 17 acres of land)

So if the farmer has 17 acres of land or more, then he will make more than $70,000 per year

Step-by-step explanation:

Use the proportions from earlier

We have the point (5, 21000)

70,000/21,000 = 3.3

To find the x-value multiply 3.3 by 5

3.3 * 5 = 16.65

We can even use the other point's values to find the exact same answer

Point (3.5, 14700)

70,000/14,700= 4.7619047619

4.7619047619 * 3.5 = 16.66 (literally about the same)

3 0
3 years ago
Find the area of the parallelogram by composing into rectangles or decomposing into triangles or other shapes as needed. 8 yd 6
Gennadij [26K]

Answer:

Below.

Step-by-step explanation:

The area = area of a rectangle on the same base and between the same parallel lines

= (15 + 6) * 8

= 21 * 8

= 168 yd^2.

8 0
3 years ago
Read 2 more answers
Given f (x) =2x-3 what is f(-15) <br><br> A. -16<br> B. -13<br> C. 7<br> D. 30
Murljashka [212]
Letter d is the answer.
5 0
3 years ago
Hellpp please! ASAPP!!
MArishka [77]

Answer:

m∠z= 58.7

Step-by-step explanation:

Remember, all triangles sum up to 180 degrees.

So, the equation would be: 31.3+90+m∠z= 180.

Step 1- Add to simplify.

(31.3+90)+m∠z= 180

121.3+m∠z= 180

Step 2- Subtract to both sides.

121.3+m∠z= 180

-121.3             -121.3

m∠z= 58.7

4 0
3 years ago
Find the modulus of the complex number 6-2i
Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

We know that

z = x + iy

where x and y are real and \sqrt{-1}=i

The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

z=6-2i

z=6+(-2)i

|z|\:=\sqrt{x^2+y^2}

|z|\:=\sqrt{6^2+\left(-2\right)^2}

    =\sqrt{6^2+2^2}

    =\sqrt{36+4}

    =\sqrt{40}

    =\sqrt{2^2}\sqrt{2\cdot \:5}

    =2\sqrt{2\cdot \:5}

   =2\sqrt{10}

Therefore, the modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

3 0
3 years ago
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