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siniylev [52]
2 years ago
14

If renting a bike cost $5 plus $2.50 per hour how much will i costs for 6 hours​

Mathematics
1 answer:
Natasha2012 [34]2 years ago
5 0

Answer:

15per 6 hours

Step-by-step explanation:

2.5x2=5x3=15

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(10n-5)÷(5)=2n-1 the left of the parentheses has to equal the right
daser333 [38]
(10n-5)/(5)= 2n-1
just divide
10/5 = 2 and -5/5 =-1
and you get the answer
2n-1= 2n-1
8 0
3 years ago
Helpppppppppp there are 2 pics attached
fiasKO [112]

Answer:

Option A

Option B

Option E

Option G

Option A and E go together

and

Option B and G go together.

4 0
3 years ago
You bike 1 mile the first day of your​ training, 1.3 miles the second​ day, 1.9 miles the third​ day, and 3.1 miles the fourth d
JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

d_1=1 mi is the distance travelled during the 1st day

d_2=1.3 mi is the distance travelled during the 2nd day

d_3=1.9 mi is the distance travelled during the 3rd day

d_4=3.1 mi is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2

Which can be rewritten using the general formula:

d_{n+1}-d_n=2(d_n-d_{n-1})

This means that

d_{n+1}=d_n+2(d_n-d_{n-1})

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi

So, the  distance travelled on the 7th day is 19.9 miles.

7 0
3 years ago
The number of games in the first round of a chess tournament is equal to 2×2×2×2×2×2. Write the number of games using an exponen
Naily [24]

Answer:

2^6

Step-by-step explanation:

2 is being multiplied 6 times meaning it would be 2 to the 6th power.

8 0
3 years ago
The first term of an arithmetic sequence is -3 and the fifteenth term is 53 what is the common difference of the sequence
saul85 [17]

Solution

The 1st term = -3

15th term = 53

15th term = a + d(n-1)

53 = -3 + d(15- 1)                       [Here n = 15)

53 + 3 = d(14)

14d = 56

d = 4

The common difference is 4.

7 0
3 years ago
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