(10n-5)/(5)= 2n-1
just divide
10/5 = 2 and -5/5 =-1
and you get the answer
2n-1= 2n-1
Answer:
Option A
Option B
Option E
Option G
Option A and E go together
and
Option B and G go together.
Answer:
19.9 miles
Step-by-step explanation:
In this problem we have:
is the distance travelled during the 1st day
is the distance travelled during the 2nd day
is the distance travelled during the 3rd day
is the distance travelled during the 4th day
We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

Which can be rewritten using the general formula:

This means that

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

So, the distance travelled on the 7th day is 19.9 miles.
Answer:
2^6
Step-by-step explanation:
2 is being multiplied 6 times meaning it would be 2 to the 6th power.
Solution
The 1st term = -3
15th term = 53
15th term = a + d(n-1)
53 = -3 + d(15- 1) [Here n = 15)
53 + 3 = d(14)
14d = 56
d = 4
The common difference is 4.