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3 years ago

14

If renting a bike cost $5 plus $2.50 per hour how much will i costs for 6 hours

1 answer:

Natasha2012 [34]3 years ago

5 0

Answer:

15per 6 hours

Step-by-step explanation:

2.5x2=5x3=15

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Of the 58 employees in a firm, 8 are considered support staff, and 7 of the employees have more than five years of experience. A

polet [3.4K]

Using statistical concepts, it is found that the number of outcomes that are possible for the complement of the union of Events J and K is of 43.

<h3>What is the union of events J and K?</h3>

It means that at least one of event J or event K is true, hence, it is composed by employees that are either considered support staff(less than 5 years of experience) or employees that have more than five years of experience, combining a total of 7 + 8 = 15 employees.

<h3>What is the complement?</h3>

The total number of outcomes of the union of J and K, plus the complement, add to the total number of 58, hence:

15 + x = 58

x = 43.

The number of outcomes that are possible for the complement of the union of Events J and K is of 43.

More can be learned about complementary events at brainly.com/question/9752956

6 0

2 years ago

Choose the answer that represents the product below as an exponential

oksano4ka [1.4K]

Answer:

2^4

Step-by-step explanation:

2*2*2*2

There are four 2's multiplied together

2 is the base and 4 is the exponent

2^4

6 0

3 years ago

Read 2 more answers

At what rate per annum ci will RS 2000 amount to RS 2315.35 in 3 years

Mashutka [201]

<u>ANSWER: </u>

Rate per annum at which CI will amount from RS 2000 to RS 2315.35 in 3 years is 5%

<u>SOLUTION: </u>

Given,

P = RS 2000

C.I = RS 2315.35

T = 3 years

We need to find the rate per annum. i.e. R = ?

We know that,

When interest is compound Annually:

$Amount $=\mathrm{P}\left(1+\frac{\mathrm{R}}{100}\right)^{n}$$

Where p = principal amount

r = rate of interest

n = number of years

$2315.35=2000 \times\left(1+\frac{R}{100}\right)^{3}$

$\left(1+\frac{R}{100}\right)^{3}=\frac{2315.35}{2000}$

$\left(1+\frac{R}{100}\right)^{3}=1.157$

$1+\frac{R}{100}=\sqrt[3]{1.157}$

$1+\frac{R}{100}=1.0500$

$\frac{R}{100}=1.05-1$

$\frac{R}{100}=0.05$

R = 5%

Hence, rate per annum is 5 percent.

3 0

3 years ago

On the first part of a journey, Alan drove a distance of x km and his car used 6 litres of fuel.

irinina [24]

Answer:

$\frac{600}{x+20}\text{ litres per 100 km}$

Step-by-step explanation:

Given,

The number of litres consumed by car in (x+20) km = 6,

So, number of litres consumed by car in 1 km = $\frac{6}{x+20}$ ,

Now, number of litres consumed by car in 100 km = 100 × litres consumed by car in 1 km

$=100\times \frac{6}{x+20}$

$=\frac{600}{x+20}$

Hence, the rate of fuel used by his car would be $\frac{600}{x+20}$ litres per 100 km.

6 0

4 years ago

Help me pleaseeeee!!!!

OLga [1]

Answer:

$2xyzx^{2} \sqrt[ 0]{xyz}$

Step-by-step explanation:

simplify the radical by breaking the radicand up into a product of know factors

8 0

3 years ago