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3 years ago

HELP PLEASE ! if right will mark as brainliest !

Mathematics

1 answer:

bekas [8.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

so pay attentyion t the numbners

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Nine times a number y plus seven is equal to a number y . Write the word sentence as an equation.

Dafna1 [17]

Answer: 9y + 7 = y

Explanation:

The phrase, "nine times a number y" is "9y" in the form of an equation. When any term is by a number, they are meant to be multiplied together. So, "9y" means "9 times y".

The phrase, "plus seven" simply means to add seven.

The phrase, "equal to number y" is "= y" because "number y" refers to that term.

And so, all together, you get 9y + 7 = y.

(Brainliest would be appreciated)

I hope this helped!

Good luck <3

4 0

2 years ago

What are the center and radius of the circle with equation (−)+(−)=?Open x minus 4 close squared . Plus . Open y minus 9 close s

lbvjy [14]

Answer:

Center and radius of the circle of the equation ${(x - 4)^{2} + (y - 9)^{2} = 1$

center = ( 4,9) Radius = 1

Step-by-step explanation:

Given -

Equation of circle is $(x - 4)^{2} + (y - 9)^{2} = 1$

The equation of circle is represented by

$\boldsymbol{\mathbf{(x - a)^{2} + (y - b)^{2} = r^{2}}}$

where a and b are center of circle and radius r

Comparing these equation

then a = 4 and b = 9 and r = 1

3 0

4 years ago

Need help! Please! Mark as brainliest!

mojhsa [17]

Answer:

Contents of the blood flow is called hemorheology in the book require addi tional clarification to be useful to you

7 0

3 years ago

Read 2 more answers

Which equation has the same meaning as y=log8 x?<br> 8^x=y<br> x=y^8<br> x=8y<br> x=8^y

a_sh-v [17]

$\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\[-0.35em] ~\dotfill\\\\ y=\log_8(x)\implies 8^y=x$

6 0

3 years ago

Evaluate the integral by interpreting it in terms of areas Draw a picture of the region the integral

denis23 [38]

Answer:

Step-by-step explanation:

The picture is below of how to separate this into 2 different regions, which you have to because it's not continuous over the whole function. It "breaks" at x = 2. So the way to separate this is to take the integral from x = 0 to x = 2 and then add it to the integral for x = 2 to x = 3. In order to integrate each one of those "parts" of that absolute value function we have to determine the equation for each line that makes up that part.

For the integral from [0, 2], the equation of the line is -3x + 6;

For the integral from [2, 3], the equation of the line is 3x - 6.

We integrate then:

$\int\limits^2_0 {-3x+6} \, dx+\int\limits^3_2 {3x-6} \, dx$ and

$-\frac{3x^2}{2}+6x\left \} {{2} \atop {0}} \right. +\frac{3x^2}{2}-6x\left \} {{3} \atop {2}} \right.$ sorry for the odd representation; that's as good as it gets here!

Using the First Fundamental Theorem of Calculus, we get:

(6 - 0) + (-4.5 - (-6)) = 6 + 1.5 = 7.5

5 0

3 years ago