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Alexeev081 [22]
2 years ago
7

6. A shipping box is shown below. How many

Mathematics
1 answer:
Nadya [2.5K]2 years ago
5 0

Answer:

can't understand your question

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In an exam a student scored 60 marks out of<br>a possible 80. What percentage is this?<br>?​
stiks02 [169]

Answer:

75%

Step-by-step explanation:

5 0
3 years ago
Graph by using the slope and the y intercept.
Mashutka [201]

1. a) equation of the line :

  • y =  \dfrac{2}{5}x   - 7

y - intercept = -7

so, it will pass through point (0, -7)

and if we plug the value of x as 5, we get

  • y =  (\dfrac{2}{5}  \times 5) - 7

  • y = 2 - 7

  • =  - 5

so, it will pass through point (5, -5) too

now, just plot the points (0 , -7) and (5 , -5) and join them.

2. b) equation of line is :

  • y =  - 3x + 5

here, y - intercept = 5

so the line passes through point (0 , 5)

now, Plugging the value of x = 1 we get :

  • y =(  - 3 \times 1) + 5

  • y =  - 3 + 5

  • y = 2

so, the given line passes through point (1 , 2)

plotting the points, we can get our required line.

6 0
2 years ago
1. On a number line, would you find −3 5/11 to the left or to the right of −3.4545? Explain how you know
AfilCa [17]

Answer:

<em> A number on the left is less than a number on the right. A number on the right is greater than a number on the left. You can also try the zoomable number line. Place these people on the number line to find who is poorest and who is richest.</em>

5 0
2 years ago
A cement walkway of uniform width has been built around an in-ground rectangular pool. the area of the walkway is 1344 square fe
Elza [17]

Answer:

6 feet.

Step-by-step explanation:

Dimensions of the Pool =80 feet long by 20 feet wide

Area of the walkway =1344 square feet.

If the width of the walkway=w

  • Length of the Larger Rectangle =80+2w
  • Width of the Larger Rectangle =20+2w

Area of the Walkway =Area of the Larger Rectangle - Area of the Pool

1344=(80+2w)(20+2w)-(80*20)\\1344=80*20+160w+40w+4w^2-80*20\\4w^2+200w=1344\\4w^2+200w-1344=0\\We factorize\\4(w^2+50w-336)=0\\4(w^2-6w+56w-336)=0\\w(w-6)+56(w-6)=0\\(w-6)(w+56)=0\\w-6=0$ or $ w+56=0\\w=6$ ft or $ w=-56$ \\Therefore, the width of the walkway , w=6 feet.

6 0
3 years ago
URGENT need answer quick
beks73 [17]

Answer:

Part A: x = 4.

Part B: The answer normally would be x = 12, but since your question asked why it has no real solution, it is because the solution (x=12) does not make the equaion true. Why? Because the value given from the equation that should make the equation true does not relate the equation in itself; hence making it have no solution.

5 0
2 years ago
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