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IrinaVladis [17]
2 years ago
15

A bag contains five red marbles, four blue marbles, and three yellow marbles. You randomly pick a marble. What is the probabilit

y the marble is red or blue?
Mathematics
1 answer:
Serga [27]2 years ago
3 0

Answer and Step-by-step explanation:

First, find the total amount of marbles.

5 + 4 + 3 = 12

There are 12 marbles in total.

The probability of picking a red or blue marble would be 9 out of 12, since it is asking for either the red marble or the blue marble.

9/12 is the answer. (Simplifies down to 3/4)

#teamtrees #WAP (Water And Plant)

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4 0
3 years ago
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sammy [17]

Answer:

2

Step-by-step explanation:

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Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
Can you help me with this like explain how and stuff, Please?
eduard

Answer:

Step-by-step explanation:I belive that the 7x+22 needs to equal 50 because they opposite angles. Hope this helped a little and can get you started

7 0
3 years ago
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