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Naddika [18.5K]
3 years ago
12

What are the solution(s) of -3(x - 1) = x - 5? O-5 and 3 O-3 O1 and 5 O 2

Mathematics
2 answers:
andre [41]3 years ago
8 0

Answer:

x = 2

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

-3(x - 1) = x - 5

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute -3:                         -3x + 3 = x - 5
  2. Add 3x to both sides:           3 = 4x - 5
  3. Add 5 to both sides:             8 = 4x
  4. Divide 4 on both sides:        2 = x
  5. Rewrite:                                 x = 2

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

  1. Substitute:                    -3(2 - 1) = 2 - 5
  2. Subtract:                       -3(1) = -3
  3. Multiply:                        -3 = -3

Here we see that -3 does indeed equal -3.

∴ x = 2 is a solution of the equation.

Alexxandr [17]3 years ago
4 0

Answer:

d) 2.

Step-by-step explanation:

i just did it

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41 \:  \:  \: years \:  \:  \: old

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Answer: y= 3x-1

Step-by-step explanation:

Equation of a straight line:

y = mx + b ------(i)

Step by Step Solution:

Step 1: Calculating Slope (m).

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m =

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m =

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Now putting value of m in equation (i)

y = 3x + b -----(ii)

Step 2: Calculating Y-intercept (b).

Lets choose the first point, (0,-1) for calculating y-intercept:

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1000 households were surveyed. 275 households own a desktop computer, 455 households own a DVD player, 405 households own two ca
icang [17]

Answer:

Step-by-step explanation:

From the given information,

Suppose

X represents the Desktop computer

Y represents the DVD Player

Z represents the Two Cars

Given that:

n(X)=275

n(Y)=455

n(Z)=405

n(XUY)=145

n(YUZ)=195

n(XUZ)=110

n((XUYUZ))=265

n(X ∩ Y ∩ Z) = 1000-265

n(X ∩ Y ∩ Z) = 735

n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)

145 = 275+455 - n(X ∩ Y)

n(X ∩ Y) = 585

n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)

195 = 455+405-n(Y ∩ Z)

n(Y ∩ Z) = 665

n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)

110 = 275+405-n(X ∩ Z)

n(X ∩ Z) = 570

a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)

n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735

n(X ∪ Y ∪ Z) = 50

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