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AnnyKZ [126]
3 years ago
10

Angel and Jayden were at track practice. The track is 2/5kilometers around. Angel ran 1 lap in 2 minutes. Jayden ran 3 laps in 5

minutes. How many minutes does it take Angel to run one kilometer?
pls, help I don't want to fail!!
Mathematics
2 answers:
SVEN [57.7K]3 years ago
6 0
5 minutes to run one kilometer
Elena-2011 [213]3 years ago
5 0

Answer:

5 minutes

Step-by-step explanation:

if one lap is 2/5 km then you  would need to run 2.5 laps to run a km and if it takes 2 minutes to run a lap then you multiply 2 minutes by the number of laps aka 2.5 so 2 times 2.5=5

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nadezda [96]

Answer:

35

Step-by-step explanation:

From the information given we can solve for x using the larger triangle

we know that the <em>angle</em> at the top is 45 degrees and the side <em>opposite</em> of it is 35, in other words we need to find the <em>adjacent,</em> or rather, x

Since we have <em>angle</em>, an <em>opposite</em> side, and we need the <em>adjacent</em>. The trig function we need to use is tan, the formula is

tan0=\frac{opposite}{adjacent}

we need to rearrange this to solve for the <em>adjacent</em>

<em />adjacent=\frac{opposite}{tan(0)}<em />

<em />x=\frac{15}{tan(45)}<em />

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3 years ago
Which expression is equivalent to -3(4x-0.50)?
MaRussiya [10]
The answer is b.
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8 0
3 years ago
Read 2 more answers
What is the perimeter of a polygon with vertices at (−2, 1) , ​ (−2, 4) ​, (2, 7) , ​ (6, 4) ​, and (6, 1) ​?
alekssr [168]
First we need the distances of the sides of the polygon, because perimeter = sum of all sides.
d =  \sqrt{{(y2 - y1)}^{2} + {(x2 - x1)}^{2} }
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d2 = \sqrt{{(4 - 7)}^{2} + {( - 2 - 2)}^{2} } \\  = \sqrt{{(- 3)}^{2} + {( -4)}^{2} } =  \sqrt{9 + 16}  \\  =  \sqrt{25}  \: = 5
d3 \: = \sqrt{{(7 - 4)}^{2} + {(2 - 6)}^{2} } \\  =  \sqrt{{(3)}^{2} +  {( - 4)}^{2} } =  \sqrt{9 + 16}  \\  =  \sqrt{25} \:  = 5
d4 = \sqrt{{(4 - 1)}^{2} + {(6 - 6)}^{2} } \\  =  \sqrt{ {(3)}^{2} +  {(0)}^{2}  }  =  \sqrt{9} \:  = 3
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p = d1 + d2 + d3 + d4 + d5
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3 years ago
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