1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
blondinia [14]
3 years ago
15

Which inequality matches the graph? A 12 B 12> c 12x D 12 5x

Mathematics
1 answer:
never [62]3 years ago
7 0
The answer is 60 I think
You might be interested in
Which of the following is not true regarding sets of numbers ?
nasty-shy [4]

D. All rational numbers are integers

6 0
4 years ago
Read 2 more answers
Quick! Help! Find the area of the composite figure
Sonbull [250]

Answer:

`100 ft

Step-by-step explanation:

5 0
3 years ago
Solve for ddd. Give an exact answer. 0.5(7d+4)=7-1.5d0.5(7d+4)=7−1.5d0, point, 5, left parenthesis, 7, d, plus, 4, right parenth
MissTica

Answer:

d = 1

Step-by-step explanation:

The equation given is:

0.5(7d + 4) = 7 - 1.5d

Expand the bracket:

3.5d + 2 = 7 - 1.5d

Collect like terms:

3.5d + 1.5d = 7 - 2

5d = 5

d = 5 / 5 = 1

4 0
3 years ago
5% of all widgets are defective. there is a 30% chance that a widget was produced at the foo factory. if a widget was produced a
VARVARA [1.3K]
A.) P(defective | foo) = P(defective & foo)/P(foo)
  4% = P(defective & foo)/30% . . . . . . . . . plug in the given data
  0.04*0.30 = P(defective & foo) = 0.012 = 1.2%

The probability that a widget was produced at the foo factory and is defective is 1.2%.

b.) P(defective | foo) ≠ P(defective) (4% ≠ 5%), so the events P(defective) and P(foo) are NOT independent.

c.) P(foo | defective) = P(defective & foo)/P(defective)
  P(foo | defective) = 1.2%/5% = 24%

The probability that a widget was produced at the foo factory given it is defective is 24%.
8 0
3 years ago
Write a system of equations and solve using elimination. Ricardo has two bills. The two bills together are $21. One bill is wort
djyliett [7]

Answer:

The worth of one bill is $20 and the worth of the other bill is $1

Step-by-step explanation:

Let

x----> the worth of one bill

y ---> the worth of the other bill

I assume x > y

we know that

x+y=21 ----> equation A

x=y+19 ---> equation B

Solve the system by elimination

Multiply equation B by -1 both sides

-x=-y-19 ----> equation C

Adds equation A and equation C

x+y=21

-x=-y-19

------------

y=21-y-19

2y=2

y=1

Find the value of x

x=y+19 -----> x=1+19=20

therefore

The worth of one bill is $20 and the worth of the other bill is $1

5 0
3 years ago
Other questions:
  • Solve for C: S = C+RC
    10·1 answer
  • A book sold 33,700 copies in its first month of release.
    15·1 answer
  • Match each equation with its solution set.
    13·1 answer
  • How are I supposed to do this ?
    5·1 answer
  • How would you solve this?
    15·1 answer
  • 2.52343454 + -34355343.99<br> NEED HELP PLZZZZZZ ASAP
    12·1 answer
  • List the factors in the expression 4r + 5s +8.<br> PLZ HELP MEEEEE!!!!!
    11·1 answer
  • Pqrs is a rhombus find the value of x and y
    13·2 answers
  • Help will mark Brainliest for the answer
    9·1 answer
  • for each of these relations on the set {1, 2, 3, 4}, decide whether it is reflexive, symmetric, antisymmetric, or transitive. {(
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!