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Andru [333]
3 years ago
13

Given the following code segment, how can you best describe its behavior? i ← 1 FOR EACH x IN list { REMOVE(list, i) random ← RA

NDOM(1, LENGTH(list)) INSERT(list, random, x) i ← i + 1 }Required to answer. Single choice.
a. This code replaces everything in the list with random numbers.
b. This code shuffles the order of the numbers in the list by removing them and inserting them back in a random place.
c. This code removes all of the numbers in the list and inserts random numbers in random places in the list.
d. This code errors by trying to access an element at an index greater than the length of the list.
Computers and Technology
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

Well, this code would box the whole body of an html document. by using the relative value for position, you are telling it to position relative to its normal position, which the top left corner is at (0,0). by using left: 50px, you are telling the box to set the left margin edge to 50px and by using top: 50px, you are telling it to set the top margin edge to 50px. by doing this shifting, the top left corner of the box, which is at (0,0) would be positioned at (50,50)

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In Java:

import java.util.*;

public class Main{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 String isbn;

 System.out.print("First 1:2 digits: ");

 isbn = input.nextLine();

 if(isbn.length()==12){

 int chksum = 0;

 for(int i = 0; i<12;i++){

     if((i+1)%2==0){      chksum+= 3 * Character.getNumericValue(isbn.charAt(i));          }

     else{          chksum+=Character.getNumericValue(isbn.charAt(i));          }  }

 chksum%=10;

 chksum=10-chksum;

 if(chksum==10){

 System.out.print("The ISBN-13 number is "+isbn+"0");}

 else{

 System.out.print("The ISBN-13 number is "+isbn+""+chksum);          }   }

 else{

     System.out.print("Invalid Input");

 }     }}

Explanation:

See attachment for explanation where comments are used to explain each line

Download txt
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hope this helps!

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