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marishachu [46]
3 years ago
14

Simplify the expression. -2/3c -9/5 + 14c + 3/10

Mathematics
2 answers:
Firlakuza [10]3 years ago
6 0

Answer:

40/3 c-3/2

Step-by-step explanation:

calculate the sum

<u>-2/3c</u>-9/5<u>+14c</u>+3/10

<u>40/3c</u> -9/5+3/10

40/3c-<u>3/2</u>

=40/3c-3/2

Andrew [12]3 years ago
5 0

Answer:

13 \frac{1}{3} c - 1 \frac{1}{2}

Step-by-step explanation:

We want to combine alike terms so

-2/3c+14c & -9/5+3/10

14c-2/3

\frac{14}{1} c -  \frac{2}{3} c

Multiply 14/1 by 3/3 to get the denominators the same

\frac{42}{3} c -  \frac{2}{3} c

Subtract

\frac{40}{3} c

simplify

13 \frac{1}{3} c

now

\frac{3}{10}  -  \frac{9}{5}

Multiply 9/5 by 2/2

\frac{3}{10}  -  \frac{ 18}{10}

Subtract

- \frac{15}{10}

Simplify

- 1 \frac{1}{2}

put both together

13 \frac{1}{3}c  - 1 \frac{1}{2}

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

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Simplify (5x2 + x – 11) – (3x² + 4x – 17)
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Step-by-step explanation:

Simplify the following:

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-(3 x^2 + 4 x - 17) = -3 x^2 - 4 x + 17:

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What is the solution to the system of equations y=-1/3x+9 and y=2/3x+12
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Answer:

{x = -3 , y = 10

Step-by-step explanation:

Solve the following system:

{y = 9 - x/3 | (equation 1)

{y = (2 x)/3 + 12 | (equation 2)

Express the system in standard form:

{x/3 + y = 9 | (equation 1)

{-(2 x)/3 + y = 12 | (equation 2)

Swap equation 1 with equation 2:

{-(2 x)/3 + y = 12 | (equation 1)

{x/3 + y = 9 | (equation 2)

Add 1/2 × (equation 1) to equation 2:

{-(2 x)/3 + y = 12 | (equation 1)

{0 x+(3 y)/2 = 15 | (equation 2)

Multiply equation 1 by 3:

{-(2 x) + 3 y = 36 | (equation 1)

{0 x+(3 y)/2 = 15 | (equation 2)

Multiply equation 2 by 2/3:

{-(2 x) + 3 y = 36 | (equation 1)

{0 x+y = 10 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{-(2 x)+0 y = 6 | (equation 1)

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Divide equation 1 by -2:

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Collect results:

Answer:  {x = -3 , y = 10

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3 years ago
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