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2 years ago

7

How many times does compounded quarterly a year mean?

1 answer:

skad [1K]2 years ago

8 0

Answer:

Interest may be compounded on all sorts of time frequencies – daily (365 times a year), monthly (every calendar month or 12 times a year), quarterly (every three months or four times a year), semi-annually (every six months or twice per year) or annually (once a year)

Step-by-step explanation:

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Graph the equation y = -3x on a graph

Dafna1 [17]

Put a dot on the -3 from the y-axis and draw a straight line from left to right.

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2 years ago

4) A zoologist was checking the weights of three gorillas. Gorilla A weighed 559 pounds, gorilla B weighed 827 pounds and gorill

miss Akunina [59]

Answer:

1,516 pounds

Step-by-step explanation:

Gorilla A weighed = 559 pounds Gorilla B weighed = 827 pounds Gorilla C weighed = 130 pounds

Total weight of the gorillas = gorilla A + gorilla B + gorilla C

= 559 pounds + 827 pounds + 130 pounds

= 1,516 pounds

Total weight of the gorillas = 1,516 pounds

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2 years ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

So

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

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2 years ago

Lauren ran for 45 minutes and traveled 3 miles. what is her rate per mile

Lady bird [3.3K]

I think that her rate per mile is 15 miniutes

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2 years ago

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A crab walk 1/12 of a mile an hour. The crab 1/5 of a mile away from the beach . How long will it take the crab to reach the bea

marysya [2.9K]

Answer:

2.4 hours

Step-by-step explanation:

$\frac{1}{5} /\frac{1}{12}$

2.4 hours

3 0

3 years ago