Your anwser is c. Y>1 y-x>0
Answer:
i think its like 2z+8
Step-by-step explanation:
Y^2-y^1/x^2-x^1
15-10/1-3
slope = -5/2
Let:
Vj = Speed of jane
Vm = Speed of mike
d = distance
t = time
Jane travels 7 mph less than 2 times as fast as Mike, therefore:
Vj = 2Vm - 7
Remeber:
distance = speed*time
Distance traveled by mike:
d=Vm*t = Vm*6
Distance traveled by jane:
d + 198 = Vj*6
where:
Vj = 2Vm - 7
d + 198 = (2Vm-7)*6
Now, let:
d=Vm*6 (1)
d + 198 = (2Vm-7)*6 (2)
Replace (1) into (2)
6Vm + 198 = 12Vm - 42
Subtract 6Vm from both sides:
6Vm + 198 - 6Vm = 12Vm - 42 - 6Vm
198 = 6Vm - 42
Add 42 to both sides:
198 + 42 = 6Vm - 42 + 42
240 = 6Vm
Divide both sides by 6:
240/6 = 6Vm/6
40 = Vm
Vm = 40mph
Replace Vm into this equation Vj = 2Vm - 7 :
Vj = 2(40) - 7 = 80 - 7 = 73mph
Answer:
6 miles.
Step-by-step explanation:
Let x be the total distance hoped by Kangaroo to the lake.
We have been given that a kangaroo hopped 1/3 of the distance to the lake with her baby in her pouch.
She hopped the remaining 7040 yards without her baby in her pouch. This means that 2/3 of total distance (x) is 7040. We can represent this information in an equation as:

Let us solve for x by multiplying both sides of our equation by 3/2.



Therefore, the total distance hoped by the kangaroo is 10560 yards.
1 mile = 1760 yards
Let us convert this distance in miles by dividing 10560 yards by 1760.




Therefore, the kangaroo hoped 6 miles to the lake.