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zalisa [80]
3 years ago
5

wendy and rick left the library at noon and cycled 480 meters to the town hall . wendy cycled at a spees of 80 meters per minute

. Rick's speed was 20 meters per minute slower than Wendy's. After cycling 0.25 of the distance Wendy stopped and waited for Rick to catch up with her. how many minute did wendy wait for rick show answer in minute
Mathematics
1 answer:
LenKa [72]3 years ago
4 0
Cycled 480 meters but a<span>fter cycling 0.25 of the distance Wendy stopped and waited for Rick to catch up 

0.25 (480) = 120 meters

</span><span>Wendy cycled at a speed of 80 meters per minute = 120 /80 = 1.5 minutes
</span><span>Rick's speed was 20 meters per minute slower than Wendy's = 120 / 60 = 2 minutes

so </span>2 minutes -  1.5 minutes = 0.5 minutes

answer
<span>Wendy waited 0.5 minutes for Rick </span>

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Answer:

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- The number of small boxes that will fill the large box 2 = 56

Step-by-step explanation:

Complete Question

Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are 4.5 inches long, 4.5 inches wide, and 8 inches tall. To transport the items to an event, you want to know how many of the small boxes will fit in larger boxes. The larger boxes are available in two sizes. Large Box 1 is 24.25 inches long, 18 inches wide, and 24 inches tall. Large Box 2 is 20.5 inches long, 18.5 inches wide, and 24 inches tall. Both the small and large boxes must remain upright.

Solution

To know how many of the small boxes will fit in larger boxes, we need to obtain the volumes of the small box, large box 1 and large box 2.

Volume of a cuboid = L × W × H

For the small box,

Length = L = 4.5 inches

Width = W = 4.5 inches

Height = H = 8 inches

Volume of the small box = 4.5 × 4.5 × 8 = 162 in³

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Height = H = 24 inches

Volume of the large box 1 = 24.25 × 18 × 24 = 10,476 in³

For large box 2

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Width = W = 18.5 inches

Height = H = 24 inches

Volume of the large box 2 = 20.5 × 18.5 × 24 = 9,102 in³

The number of small boxes that'll fill the large box 1 = (10,476/162) = 64.667 = 64 small boxes (rounded down because the fraction cannot be forced into the large box 1.

The number of small boxes that will fill the large box 2 = (9,102/162) = 56.185 = 56 small boxes.

Hope this Helps!!!

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