What is the remainder when a^3 - 4 is divided by a+2?

Find the value to the nearest tenth

WITCHER [35]

Answer:

twenty five point four ....25.4

6 0

3 years ago

I need help with this

emmasim [6.3K]

Answer:

Here,

Angle TUV + Angle NUV=TUV

By substituting the provided or given value ls in the question we obtain,

1+38x+66 Degree= 105x

1+66 Degree= 67x

67 Degree= 67x

1 Degree = x

x = 1 Degree

Therefore

Angle TUN=1+38x=39

Angle NUV=66 Degree

Therefore

1+38x+66 Degree= 105x

=39 Degree+66 Degree= 105 Degree

Therefore

Angle TUV=105 Degree

6 0

3 years ago

Point M is located at (4,6) on a coordinate grid. Point M is translated 8 units to thr left and 9 units down to create point M'.

nata0808 [166]

Well, i would use the distance formula to find the distance between the two points. Only issue- you do not have the other point, so lets find it!

We have the point 4,6. 4 is the x, and 6 is the y.

Lets start with 4 since the x works with the left and right aspect of the location. It says M has been translated 8 units to the left, meaning we go back 8. So if we are at 4, and we go back (A.K.A. Subtract) 8, we will be at -4.

Now lets move onto the y, which works with the up and down aspect of the location. It says M has been translated 9 unites down, meaning the point will be heading down and getting smaller. So if we are at 6, and we go down (A.K.A. subtract) 9, then we will be at -3.

So now we have the coordinates of point M (4,6) and point M' (-4,-3) so we can now complete the distance formula!

The distance formula helps determine the distance between two points. It looks like this: D = √(x₂-x₁)²+(y₂-y₁)²

Though it does not matter which order you use the coordinates in, i am choosing to use M and then M'.

So, starting with the X, X₂ will be -4 and X₁ will be 4.
Again, starting with the Y, Y₂ will be -3 and Y₁ will be 6.

So, the formula plugged in will look like this: d = √(-4 - 4)² + (-3 - 6)²

Solving it out, we first need to work within the parenthesis. Can you solve it?

Our outcome will be this: -8² + -9². But, since we are squaring (And a negative times a negative equals a positive) you can just write 8² + 9²

8²= 64
9²= 81

64+81 = 145.

So, the distance between point M and point M' would be 145 units

Hope this helps!

If it does not, please let me know so i can try to help!

4 0

3 years ago

Please help me find the total area of the composite figure below (geometry)

Akimi4 [234]

Answer:

lw + $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$ ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = $\frac{1}{2}$ × π × r²

Given that,

diameter of the semi-circle is ⇒ l

∴ radius ⇒ l / 2

Let us find it now.

Area = $\frac{1}{2}$ × π × r²

Area = $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$

Secondly, let us find the area of the rectangle.

Area = length × width

Given that,

length ⇒ l

width ⇒ w

Let us find it now.

Area = length × width

Area = l ×w

Area = lw

And now let us find the total area.

Total area = Area of the rectangle + Area of the semi - circle

Tota area = lw + $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$

8 0

2 years ago

Mr. Rifkin had 240 digital and manual cameras. After donating 82 digital cameras and 26 manual cameras, he had 3 times as many d

Oliga [24]

He started with 184 digital cameras and 56 manual cameras

Work--> d + m = 240 equation 1 (d-82) = 3(m-26) equation 2d - 82 = 3m - 78d - 3m = 82 - 78d - 3m = 16 equation 2 simplified d + m = 240d - 3m = 16 subtract equation 1 from equation 2--------------- -4m = -224 m = -224/-4 m = 56 d + m = 240d = 240-md = 240-56d = 184

4 0

3 years ago