First two rolls have to be 1-4 that is 2/3 chance twice and the third can be 4or 5
2/3*2/3*1/3 + the chance that the fourth is the 5 or 6.
2/3*2/3*2/3*1/3
So the solution is : P=2/3*2/3*1/3 + 2/3*2/3*2/3*1/3
Answer:
-2k + 6
hope its right
-2k - (-5) + 1
You should always switch the signs to their opposites if you're mutiplying a negative such as the - (-5) Hope I make sense
-2k + 5 + 1
-2k + 6
Answer: 0.16666666666
Step-by-step explanation:lol
Answer:
f(-2/3) = -1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 3x + 1
f(-2/3) is x = -2/3
<u>Step 2: Evaluate</u>
- Substitute: f(-2/3) = 3(-2/3) + 1
- Multiply: f(-2/3) = -2 + 1
- Add: f(-2/3) = -1
Answer:
B. (8, 4)
Step-by-step explanation:
Hope this helps!
