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bearhunter [10]
2 years ago
7

The population of fish in a take was approximately 5.4 * 10 ^ 4 in 2012. The next year, 2013population tripled What was the oppr

oximate population of fish in this in 2013?
Pleaseeee
Mathematics
1 answer:
Cerrena [4.2K]2 years ago
6 0
5,4* 10^4 = 54000in 2012.
2013 = 54000*3 = 5,4*3* 10^4 = 162000 fishes. 1,62 *10^ 5
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Answer:

The 13th term is 81<em>x</em> + 59.

Step-by-step explanation:

We are given the arithmetic sequence:

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Recall that for an arithmetic sequence, each subsequent term only differ by a common difference <em>d</em>. In other words:

\displaystyle \underbrace{-3x - 1}_{x_1} + d = \underbrace{4x + 4} _ {x_2}

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The common difference is (7<em>x</em> + 5).

To find the 13th term, we can write a direct formula. The direct formula for an arithmetic sequence has the form:

\displaystyle x_n = a + d(n-1)

Where <em>a</em> is the initial term and <em>d</em> is the common difference.

The initial term is (-3<em>x</em> - 1) and the common difference is (7<em>x</em> + 5). Hence:

\displaystyle x_n = (-3x - 1) + (7x+5)(n-1)

To find the 13th term, let <em>n</em> = 13. Hence:

\displaystyle x_{13} = (-3x - 1) + (7x + 5)((13)-1)

Simplify:

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