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zubka84 [21]
3 years ago
15

BRAINLIEST!URGENT! Please help if you can. If you know the answer, please leave an explanation and I will mark you brainliest!​

Mathematics
1 answer:
Dafna1 [17]3 years ago
7 0
The vertex form of a quadratic equation is y = n(x − h)2 + k, where (h, k) gives the coordinates of the vertex of the parabola in the xy-plane and the sign of the constant n determines whether the parabola opens upward or downward.

If n is negative, the parabola opens downward and the vertex is the maximum.

The given equation has the values h = 3, k = a, and n = −1.

Therefore, the vertex of the parabola is (3, a) and the parabola opens downward.

Thus, the parabola’s maximum occurs at (3, a)

Ans D
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Line m is drawn so that it is perpendicular to two distinct planes, Q and R. What must be true about planes Q and R?
UNO [17]
B. are parallel.

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Since it doesn't state that two planes intersect with each other, it is safe to assume that only line m is their connection. The planes are parallel with each other. </span>
7 0
3 years ago
In Ellen's math class, there are 2 boys for every 3 girls . What is the the following ratio of boys to girls in the class ?
IrinaK [193]
Based on the ratio of boys/girls We can infer that the only possibility for Ellen's math class would be answer B. 14/21
4 0
3 years ago
Whats another way to write 171.9%
Nastasia [14]
p\%=\frac{p}{100}\\\\171.9\%=\frac{171.9}{100}=\frac{171.9\cdot10}{100\cdot10}=\frac{1719}{1000}=\boxed{1\frac{719}{1000}=1.719}
3 0
3 years ago
Solve this question peasents nah jk lol
Zina [86]

v = √16 · √d

d = 300 ft

v = √16 · √300

v = √16 · √100 · √3

v =  4  ·  10  · √3  

<em>v = 40√3  ft/sec  </em>  <== simplified radical form

That's about 69.3 feet per sec, or 47.2 miles per hour.

5 0
3 years ago
A projectile is fired with an initial velocity of 550 feet per second at an angle of 70 degrees with the horizontal. In how many
sukhopar [10]

Answer:

time = 32.1 seconds.

Step-by-step explanation:

Remark.

The very first thing about this question that you must understand is that only the vertical part of the 550 feet per second matters.

That's the part of the velocity that works against gravity. The object of this question is this: how long does it take for the rocket to get from 550 feet per second to 0 when the rocket will stop and begin to fall back to earth?

t = 32.1 seconds is the answer.

Step One

Find the vertical velocity.

The formula for the vertical speed is V_vertical = 550 * Sin(70)

Vv = 516.8 feet per second. That is just a formula for finding the vertical velocity.

Step Two

What is the acceleration for this question?

You have no doubt heard the expression "What goes up much come down."

It is certainly true on planet earth. The force of gravity <em><u>always</u></em> acts downwards. The rocket's velocity is acting upwards. That's why the rocket goes up in the first place. The measurement for acceleration is 32.2 feet / second^2 and it is downwards.

The meaning of that number is that for every second that an object is moving up, it loses a velocity amount of 32 feet/sec. So the rocket is slowing down.

Step Three

Write your givens and what you need.

t = ??

vi = 516.8 feet / sec

a = - 32.2 feet / sec ^2

vf = 0

Step Four

What is the formula

a = (vf - vi)/t  or in this case

t = (vf - vi/a

Step Five

Solve using the givens.

t = (0 - (+)516.8)/-32.2

t = (0 - 516.8)/-32.2

t = - 516.8 / - 32.2

t = 16.05 seconds

Step Six

That is the time taken to go to the maximum height. Physics says that it will take the same amount of time to come down. The total time in the are = 2 * 16.05 = 32.1 seconds

So your answer is 32.1 seconds.

Note

There is absolutely no other way to do this problem. You should never have been given it without some sort of background in physics. All of the facts I have used have to be verified by experiment. These are

1. Only the vertical velocity matters. It is found by Vv = V* sin(70)

2. The acceleration due to gravity acts down.

3. The value of the acceleration = 32.2 feet/sec^2

4. The time take to complete 1/2 the journey (up to where the rocket stops) is 16.05 seconds.

5. The total time is double the going up time.

Note Two

You might be able to do this by means of energy, but that also involves physics and the time would have to be determined using this approach anyway.

I pass this along to see if anyone can do it using non-physics methods. If they can, I'll tip my hat in their direction.

5 0
3 years ago
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