Since we need to find the point at which the 2 lines intersect at the x-axis, we need to find where the 2nd line intersects the x axis, by plugging in y=0.
x-2(0)=4
x=4
Therefore, at (4,0).
Now we plug in (4,0) at the first equation.
4b+3(0)=10
4b=10
b=5/2
Therefore, at b=5/2
Answer:
(-1,-1)
Step-by-step explanation:
finding y
-6x + 5y = 1
+ (6x + 4y = -10)
---------------------------
9y = -9
y = -1
finding x
-6x + 5(-1) = 1
-6x - 5 = 1
+ 5 = +5
-6x = 6
x= -1
It is 555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555
Answer:
s = 6, r = 8 or s = 4, r = 7
Step-by-step explanation:
2r - s = 10
2r = 10 + s
r = 5 + s/2 --(1)
rs - s^2 = 12 --(2)
sub (1) into (2):
(5 + s/2)s - s^2 = 12
5s + 0.5s^2 - s^2 = 12
-0.5s^2 + 5s - 12 = 0
s^2 - 10s + 24 = 0
(s - 6)(s - 4) = 0
therefore s = 6 or s = 4
when s = 6, r = 8 and when s = 4, r = 7
if you would like to discover more about simultaneous equations, you can have a look at my Instagram page (learntionary). I'll be posting mathematics related stuff there and some of my notes (simultaneous enq notes are already posted!)
The answer is -3, i had a test with the same question
