All categories

4 years ago

On a coordinate plane, a line goes through (negative 3, negative 4) and (3, 0).

Mathematics

1 answer:

arsen [322]4 years ago

5 0

Answer:

The slope is Negative three-halves and contains the point (0, 2).

Step-by-step explanation:

(-3,-4)(3,0)

M= -4/-6 = 2/3

⊥M = -3/2

0 = 2/3(3) + B

B=2

You might be interested in

Can someone please answer this question I am confused

Oksana_A [137]

Answer:

Step-by-step explanation:

6 0

4 years ago

Can somebody help me please?

madreJ [45]

Factor
(x+7)(x-2)

Proof
7-2=5
7*-2=-14

Zeros
x+7=0
x=-7

x-2=0
x=2

Final answer: C

3 0

3 years ago

Read 2 more answers

HELP PLSSSSSSSSSS ASAP

seropon [69]

Answer:

1. 4 gal= 16 qt.

2. 6 qt= 12 pt.

3. 11 pt= 176 fl oz.

4. 18 c= 144 fl oz.

5. 48 qt= 12 gal.

6. 17 gal= 136 pt.

7. 19 qt= 76 c.

8. 256 c= 16 gal.

9. 12 gal= 96 pt.

10. 28 c= 14 pt.

11. 17 c= 136 fl oz.

12. 128 fl oz= 16 c.

13. 8 gal= 32 qt.

14. 20 qt= 640 fl oz.

15. 4 qt= 8 pt.

16. 18 qt= 72 c.

+ if this helped you, please consider marking it the Brainliest.

8 0

3 years ago

What is differential drive steering method?

tangare [24]

Differential<span> wheeled robot is a mobile robot whose movement is based on two separately driven wheels placed on either side of the robot body. It can thus change its direction by varying the relative rate of rotation of its wheels and hence does not require an additional </span>steering<span> motion.</span>

8 0

3 years ago

The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi

Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}$

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Now, $z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64$

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

$z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07$

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

6 0

4 years ago