Quadratics formula 4x^2+3x-1=0
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Answer:
Step-by-step explanation:
Given equation of line is:
y = -4x+9
Comparing it with the standard form
y = mx+b
m = -4
As we know that the product of slopes of perpendicular lines is -1
Let m1 be the slope of perpendicular line
m * m1 = -1
-4 * m1 = -1
m1 = -1/-4
m1 = 1/4
In order to find the value of b, putting the point in standard form
5 = (1/4)*4 + b
5 = 1 + b
b = 5-1
b = 4
Putting the value of b and m1 in standard form
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