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Setler79 [48]
3 years ago
5

I need help- please help meh :')

Mathematics
2 answers:
serious [3.7K]3 years ago
7 0
These are rounded.

Question 1: 38.8
Question 2: 115.4

I don’t know how they want you to do the rest of those big questions on the right I don’t use the same methods as your school.
Slav-nsk [51]3 years ago
3 0

Answer:

1 equals 2.6

2 equals  1.8

Step-by-step explanation:

just divide

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5 (2x-4)-3 (x-2)=4x-2
ipn [44]

Answer:

Step-by-step explanation:

Year it’s the exponents

3 0
4 years ago
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Nat2105 [25]

- 3x \times 8x =   { - 24}^{2}

4 0
3 years ago
Help me on this please my assignment is DUE TMR ITS 9:50 PM I EXPLAIN PLEASE
gregori [183]

Answer: The answer will be 10^6.

Step-by-step explanation:

This is because when you move the decimal place 6 places to the right. You will go from 0.63 --> 630,000. Hope I helped!!!

3 0
4 years ago
The mother is really tall (T) and the allele for this particular trait is dominant to the short (t) gene. The fathers phenotype
stiks02 [169]

If tall is completely dominant over short, then the mother's genotype is either TT or Tt. The father is short so his genotype is tt.

Crossing TT with tt produces only heterzygous offspring with genotype Tt. Then the genotypic and phenotypic ratios are 0 TT : 1 Tt : 0 tt and 1 tall : 0 short, respectively. As percentages, these would

• geno:   0% TT : 100% Tt : 0% tt

• pheno:   100% tall : 0% short

Crossing Tt with tt on the other hand produces offspring with genotype either Tt or tt with equal probability, so that the geno and pheno ratios are 0 TT : 1 Tt : 1 tt and 1 tall : 1 short. As percentages,

• geno:    0% TT : 50% Tt : 50% tt

• pheno:   50% tall : 50% short

8 0
2 years ago
Male cardinal birds sing to attract females. An ornithologist wants to test the claim that the true mean duration of songs sung
Inessa05 [86]

Answer:

t=\frac{6.31-6}{\frac{1.2}{\sqrt{35}}}=1.5283    

d. 1.5283

Step-by-step explanation:

Data given and notation    

\bar X=6.31 represent the sample mean    

s=1.2 represent the sample standard deviation    

n=35 sample size    

\mu_o =6 represent the value that we want to test    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is higher than 6 seconds, the system of hypothesis are :    

Null hypothesis:\mu \leq 6    

Alternative hypothesis:\mu > 6    

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{6.31-6}{\frac{1.2}{\sqrt{35}}}=1.5283    

d. 1.5283

8 0
3 years ago
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