Givens
Petri Dish A sees a double ever 10 minutes
Petri Dish B sees a double ever 6 minutes
Consequences
A doubles 60 / 10 = 6 times.
B doubles 60 / 6 = 10 times.
Solution
If you work best with numbers then suppose there are 100 bacteria in both dishes at the beginning
A = 100 * 2^6
B = 100 * 2^10
A will have 100 * 64 = 6400 bacteria growing inside A
B will have 100 * 1024 = 102400 bacteria growing inside B
B/A = 102400 / 6400 = 16
There are 16 times as many in B than in A. <<<< Answer
Answer:
Step-by-step explanation:
No . B' (reflection of B) and C' (reflection of C) are in the right position, but D' should be at (4, 1) and A' should be at (-2,-4).
Function B
the slope is actually consistent unlike function a, also if u graphed it out it’s function b
137 - 16X = Y
Since Lorraine is picking blackberries in her backyard at a rate of 15 berries per minute, and after 16 minutes of picking, there are still 137 blackberries left to pick, to determine an equation that models how many berries are left (y) after x minutes of picking, the following calculation must be performed:
137 - 16X = Y
Thus, for example, after 5 minutes the calculation would be as follows:
- 137 - 16 x 5 = Y
- 137 - 80 = Y
- 57 = Y
Learn more about maths in brainly.com/question/25989509
Answer:
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Step-by-step explanation:
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