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3 years ago

11

Lori bought 6,000 grams of cayenne pepper and 2 kilograms of black pepper. How many grams of pepper did she buy all together?

1 answer:

wel3 years ago

5 0

Lori bought 5,300 grams of pepper all together.

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I need help on this question

krek1111 [17]

Answer: IV

Step-by-step explanation:

I=1

II=2

AND

III=3

SO,

IV HAS TO EQUAL 4

3 0

3 years ago

Read 2 more answers

Find the approximate value of the circumference of a circle with the given radius. Use = 3.14. Round your results to one more de

melamori03 [73]

19.7 I believe is the answer.... I'm sorry if that's wrong.

5 0

3 years ago

1. A package contains 7 red candies, 4 blue candies, and 3 green candies. Three candies are drawn

erastovalidia [21]

Answer:

the answer i got was 0.214

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4 years ago

Trina uses 8.6 pints of blue paint and white paint to paint her bedroom walls.

max2010maxim [7]

<h3>Trina uses 3.44 or $\frac{ 17.2}{5}$ pints of white paint</h3>

<em><u>Solution:</u></em>

Given that,

Trina uses 8.6 pints of blue paint and white paint to paint her bedroom walls

3/5 of the amount is blue paint, and the rest is white paint

From given,

3/5 of 8.6 pints is blue paint

$Remaining = 1 - \frac{3}{5}\\\\Remaining = \frac{2}{5}$

Thus, 2/5 of 8.6 pints is white paint

<em><u>How many pints of white paint did she use to paint her bedroom walls? </u></em>

$White\ paint = \frac{2}{5} \times 8.6\\\\White\ paint = \frac{17.2}{5}\\\\White\ paint = 3.44$

Thus she uses 3.44 or 17.2/5 pints of white paint

5 0

3 years ago

Match the equations representing parabolas with their directrixes. y + 8 = 3(x + 2)2 y − 14 = -(x − 3)2 y + 7.5 = 2(x + 2.5)2 y

Shkiper50 [21]

Answer:

Part 1) $y+8=3(x+2)^{2}$ -----> $y=-8.08$

Part 2) $y-14=-(x-3)^{2}$ ----> $y=14.25$

Part 3) $y+7.5=2(x+2.5)^{2}$ ----> $y=-7.625$

Part 4) $y-17=-(x-3)^{2}$ -----> $y=17.25$

Part 5) $y+7=(x-4)^{2}$ ----> $y=-7.25$

Part 6) $y-6=-(x-1)^{2}$ ----> $y=6.25$

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

$y-k=\frac{1}{4p}(x-h)^{2}$

where

(h,k) is the vertex

The directrix is

$y=k-p$

case 1) we have

$y+8=3(x+2)^{2}$

the vertex is the point (-2,-8)

$\frac{1}{4p}=3$

$p=\frac{1}{12}$

The directrix is equal to

$y=-8-\frac{1}{12}=-8.08$

case 2) we have

$y-14=-(x-3)^{2}$

the vertex is the point (3,14)

$\frac{1}{4p}=-1$

$p=-\frac{1}{4}$

The directrix is equal to

$y=14+\frac{1}{4}=14.25$

case 3) we have

$y+7.5=2(x+2.5)^{2}$

the vertex is the point (-2.5,-7.5)

$\frac{1}{4p}=2$

$p=\frac{1}{8}$

The directrix is equal to

$y=-7.5-\frac{1}{8}=-7.625$

case 4) we have

$y-17=-(x-3)^{2}$

the vertex is the point (3,17)

$\frac{1}{4p}=-1$

$p=-\frac{1}{4}$

The directrix is equal to

$y=17+\frac{1}{4}=17.25$

case 5) we have

$y+7=(x-4)^{2}$

the vertex is the point (4,-7)

$\frac{1}{4p}=1$

$p=\frac{1}{4}$

The directrix is equal to

$y=-7-\frac{1}{4}=-7.25$

case 6) we have

$y-6=-(x-1)^{2}$

the vertex is the point (1,6)

$\frac{1}{4p}=-1$

$p=-\frac{1}{4}$

The directrix is equal to

$y=6+\frac{1}{4}=6.25$

5 0

3 years ago