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Free_Kalibri [48]
3 years ago
5

Write a quadratic function f whose zeros are 6 and 1

Mathematics
1 answer:
Ratling [72]3 years ago
4 0

Answer:

x^2-7x+6

Step-by-step explanation:

(x-6)(x-1)

x^2-1x-6x+6

x^2-7x+6

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Select the expression that is equivalent to (picture)
seraphim [82]
The answer to this question is x^(rt + s) since (x^r)^t becomes x^(rt) by the exponent power of a power property. Then multiplying powers of the same base results in the exponents being summed.
6 0
3 years ago
The surface area of this rectangular prism is 1,414 square meters. What is the volume?
Mice21 [21]

Answer:

2940

Step-by-step explanation:

Surface Area of a rectangular prism is 2(LW)+2(HW)+2(LH)

We have that the surface area is 1414 where L=c , H=20, W=7

Let's plug all of this in to solve for c:

2(LW)+2(HW)+2(LH)=1414

2(c*7)+2(20*7)+2(c*20)=1414

14c+280+40c=1414

54c+280=1414

54c=1414-280

54c=1134

c=1134/54

c=21

Now the volume of a rectangular prism is V=L*W*H

So plug in our values L=21, H=20, W=7

V=21*20*7=2940

7 0
3 years ago
What is the solution to the system:<br> x-y-2 z=4<br> -x + 2 y +z =1<br> -x +y-3 z+11
mixer [17]
The answer to the question

8 0
3 years ago
Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two over three
otez555 [7]

Answer:

y_Q=\dfrac{21}{5}=4.2

Step-by-step explanation:

If the point Q that is located two over three the distance from point P to point R, then PQ:QR=2:3.

Use formula to find the coordinates of the point Q:

x_Q=\dfrac{3x_P+2x_R}{3+2}\\ \\y_Q=\dfrac{3y_P+2y_R}{3+2}

In your case, P(-2,7) and R(1,0), then

x_Q=\dfrac{3\cdot (-2)+2\cdot 1}{3+2}=\dfrac{-4}{5}\\ \\y_Q=\dfrac{3\cdot 7+2\cdot 0}{3+2}=\dfrac{21}{5}

6 0
3 years ago
Can someone please help me (6y-22) = (y-11)
Pepsi [2]

Answer:

<h3>2.2</h3>

Step-by-step explanation:

  • (6y-22) = (y-11)
  • 6y-22 = y-11
  • 6y-y = -11+22
  • 5y = 11
  • y = 11/5
  • y = 2⅕ or 2.2

5 0
3 years ago
Read 2 more answers
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