We can solve this problem by referring to the standard
probability distribution tables for z.
We are required to find for the number of samples given the
proportion (P = 5% = 0.05) and confidence level of 95%. This would give a value
of z equivalent to:
z = 1.96
Since the problem states that it should be within the true
proportion then p = 0.5
Now we can find for the sample size using the formula:
n = (z^2) p q /E^2
where,
<span> p = 0.5</span>
q = 1 – p = 0.5
E = estimate of 5% = 0.05
Substituting:
n = (1.96^2) 0.5 * 0.5 / 0.05^2
n = 384.16
<span>Around 385students are required.</span>
Amar makes 8 dollars an hour for raking leaves
8
Answer:
a diagram is necessary. please provide a diagram.
Answer:
258
Step-by-step explanation:
Set up the two equations needed (x is the adult tickets and y is the student tickets)
x+y=372
6x+2y=1776
Solve by elimination
-2(x+y=372)
=-2x-2y=-744
Cancel like figures:
-2x-2y=-744
6x+2y=1776
= 4x=1032
x=258
D=dollars earned
T=time spent painting the fence.
(1,5) (2,10) (3,15)
D=5T
