Answer:
i need more \\
Explanation:
Chemical cold packs should be used for bone and joint injuries because they are generally colder than ice and stay cold longer.
A.
True
B.
False
Reset
Answer:
see explaination
Explanation:
void insertion( int e,int *x, int start, int end)
{
if (e >= x[end])
x[end+1] = e;
else if (start < end)
{
x[end+1] = x[end];
insertion(e, x, start, end-1);
}
else
{
x[end+1] = x[end];
x[end] = e;
}
}
void insertion_recurssion(int *b, int start, int end)
{
if(start < end)
{
insertion_sort_recur(b, start, end-1);
insertion(b[end], b, start, end-1);
}
}
void main()
{
insertion_recurssion(x,0,5);
}
Answer:
- public static String bothStart(String text1, String text2){
- String s = "";
-
- if(text1.length() > text2.length()) {
- for (int i = 0; i < text2.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }else{
- for (int i = 0; i < text1.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }
- }
Explanation:
Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).
<em />
Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).
There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).
If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.
The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>
<em />
At the end, return the s as output (Line 21).
Answer:
That would be (d) All of these. I hope this helps you!
Answer:
def nametag(first_name, last_name):
return("{} {[0]}.".format(first_name, last_name))
print(nametag("Jane", "Smith"))
# Should display "Jane S."
print(nametag("Francesco", "Rinaldi"))
# Should display "Francesco R."
print(nametag("Jean-Luc", "Grand-Pierre"))
# Should display "Jean-Luc G."
Explanation:
First you must think about that the question ask about the first letter for last_name, remember [0] is the first letter not [1], the other part is about format function and its order
