Question

-3x^2+12x-8 in vertex form using the completing the square method! ASAP PLEASE WILL MARK U WHATEVER YOU WANT! WORK NEEDED

Answer 1

Answer:

 -3x2 + 12x - 8

Step-by-step explanation:

Equation at the end of step 1

 ((0 -  3x2) +  12x) -  8

STEP

2

:

STEP

3

:

Pulling out like terms

3.1     Pull out like factors :

  -3x2 + 12x - 8  =   -1 • (3x2 - 12x + 8)  

Trying to factor by splitting the middle term

3.2     Factoring  3x2 - 12x + 8  

The first term is,  3x2  its coefficient is  3 .

The middle term is,  -12x  its coefficient is  -12 .

The last term, "the constant", is  +8  

Step-1 : Multiply the coefficient of the first term by the constant   3 • 8 = 24  

Step-2 : Find two factors of  24  whose sum equals the coefficient of the middle term, which is   -12 .

     -24    +    -1    =    -25  

     -12    +    -2    =    -14  

     -8    +    -3    =    -11  

     -6    +    -4    =    -10  

     -4    +    -6    =    -10  

     -3    +    -8    =    -11  

     -2    +    -12    =    -14  

     -1    +    -24    =    -25  

     1    +    24    =    25  

     2    +    12    =    14  

     3    +    8    =    11  

     4    +    6    =    10  

     6    +    4    =    10  

     8    +    3    =    11  

     12    +    2    =    14  

     24    +    1    =    25  

Answer 2

Answer: y=−3(x−2)^2+4

Step-by-step explanation:

f(x)=-3*x^2+12*x+-8

f(x)=-3*(x^2+-4*x+8/3) ( Factor out )

f(x)=-3*(x^2+-4*x+(-2)^2+-1*(-2)^2+8/3) ( Complete the square )

f(x)=-3*((x+-2)^2+-1*(-2)^2+8/3) ( Use the binomial formula )

f(x)=-3*((x+-2)^2+1*-4/3) ( simplify )

f(x)=-3*(x+-2)^2+4 ( expand )