I'm assuming you need to find the equation of that line. If that's not what you need, you can stop here, because that's what I'm going to calculate.
When we're working with the equation of a line, we know it's easy to work with if it's in the form of a "slope / intercept" equation.
That's Y = (slope) · x + (y-axis intercept)
We already know the slope of this line, because the question gave it to us. The slope is ' 8 ' . So we know the equation will be Y = 8x + (y-intercept) .
OK. We also know a point on the line ... (4, 3).
That tells us: When x=4 on this line, y=3 .
Take the equation, and put this point into it.
Y = 8x + (y-intercept)
(3) = 8(4) + y-intercept
3 = 32 + y-intercept
Subtract 32 from each side:
-29 = y-intercept
So the equation of the line is: <em>Y = 8x - 29</em>
First, simplify the parenthesis. You’ll get:
1/4(4z)+7=-z+1
Then multiply 1/4 by 4z. You’ll get:
z+7=-z+1
Love like terms to the same side. I wanted to have the variable positive on time, so I moved variables to the left and constants to the right. You’ll get:
2z=-6
Divide both sides by 2. You’ll get :
z=-3
<span>the product of one term of a multiplicand and one term of its multiplier.</span>
Answer:
y=-3x-5
Step-by-step explanation:
the picture below is how i did it