X actually equals the cube root of 6
![{x}^{3} - 6 = 0 \\ {x}^{3} = 6 \\ x = \sqrt[3]{6}](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B3%7D%20%20%20-%206%20%3D%200%20%5C%5C%20%20%7Bx%7D%5E%7B3%7D%20%20%3D%206%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B6%7D%20)
Let's solve and find out.
4(2n - 4) + 3 = 8n - 19
8n - 16 + 3 = 8n - 19
8n - 13 = 8n - 19
-13 = -19
-13 and -19 are not equal, so the equation has no solutions.
Answer:
A. 0
Answer:
Science? :)
Step-by-step explanation:
Answer:
0.84 or 16
Step-by-step explanation:
Multiply denominator by whole number then add that number to the nominator. Which would be 5 times 1 plus 3. SO 5+3 IS 8 and you keep the denominator so the first one is 8/5
