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marshall27 [118]
3 years ago
13

Expand and simplify (x-3)(2x+1)(x+1)

Mathematics
1 answer:
Eddi Din [679]3 years ago
8 0
<h2>2x³ - 3x² - 8x -3</h2><h2>---------------------------</h2>

<u>Step-by-step explanation:</u>

(x-3)(2x+1)(x+1)

(2x² - 6x + x - 3)(x+1)

(2x² - 5x - 3) (x+1)

2x³ -5x² -3x + 2x² -5x - 3

2x³ - 3x² - 8x -3

<h2>---------------------------</h2><h2>FOLLOW ME</h2>
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Find the sum of 7/13 and 11/26.
timofeeve [1]

Answer:

The sum of 7/13 and 11/26 is 25/26.

Step-by-step explanation:

First off you find the LCM (Least Common Multiple) between the denominators which are 13 and 26 in this case. The LCM between 13 and 26 would be 26. You then change 13 to the denominator of 26. 13x2 is 26 so whatever you do to one side or one part, you have to do to the other. Now, you will multiply 7x2 to get 14. Your final fractions are 14/26 and 11/26. When you add 14/26 and 11/26, you get 25/26. Hope this helps! :)


<h2>CloutAnswers</h2>
4 0
3 years ago
Read 2 more answers
Solve for t <br> –9.96 + 9.9t = 1.54 + 7.7t + 7.2t
timama [110]

Answer:  -2.3

Step-by-step explanation:

–9.96 + 9.9t = 1.54 + 7.7t + 7.2t

–9.96 + 9.9t = 1.54 + 14.9t

-9.96 - 5t = 1.54

-5t = 11.5

t = -2.3

5 0
3 years ago
Refer to the equation 2x − 6y = 12 Create a table of values for at least 4 points. Show your work
natka813 [3]

Answer: The table and figure are given below,

Solution:

The given equation is 2x-6y=12.

put x=0 in the equation.

2(0)-6y=12

-6y=12

y=-2

Similarly find the values of y at different values of x. The values are shown in the table.

From table it is notices that the value of y=-2 for x=0, y=-1 for x=3, y==-3 for x=-3, y=0 for x=6.

Plot these points in the coordinate plane and joint them by a straight line.

The gra his shown in below figure.

6 0
3 years ago
Read 2 more answers
How do you solve -2(x+5)=4
fenix001 [56]

Answer:

<h2>x = -7</h2>

Step-by-step explanation:

-2(x+5)=4\qquad\text{divide both sides by (-2)}\\\\\dfrac{-2\!\!\!\!\diagup(x+5)}{-2\!\!\!\!\diagup}=\dfrac{4\!\!\!\!\diagup^2}{-2\!\!\!\!\diagup_1}\\\\x+5=-2\qquad\text{subtract 5 from both sides}\\\\x+5-5=-2-5\\\\x=-7

5 0
3 years ago
Read 2 more answers
If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find ƒ(-1) + 5g(-3).<br><br> -40<br> -38<br> 7
EastWind [94]
f(x) = x^2 + 1 \\ &#10;g(x) = 3x + 1

You can do this in parts.
f(-1) = (-1)^2 + 1 = 1 + 1 = 2
g(-3) = 3(-3) + 1 = -9 + 1 = -8
So, 5g(-3) = 5(-8) = -40.
So f(-1) + 5g(-3) = 2 - 40 = -38

Or you can do this as one big chunk.
f(-1) + 5g(-3)
=[(-1)^2+1] + 5[3(-3) + 1] \\&#10;= (2) + 5(-9 + 1) \\&#10;= 2 + 5(-8) \\&#10;= 2 - 40 \\ = -38
7 0
3 years ago
Read 2 more answers
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