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marshall27 [118]
3 years ago
13

Expand and simplify (x-3)(2x+1)(x+1)

Mathematics
1 answer:
Eddi Din [679]3 years ago
8 0
<h2>2x³ - 3x² - 8x -3</h2><h2>---------------------------</h2>

<u>Step-by-step explanation:</u>

(x-3)(2x+1)(x+1)

(2x² - 6x + x - 3)(x+1)

(2x² - 5x - 3) (x+1)

2x³ -5x² -3x + 2x² -5x - 3

2x³ - 3x² - 8x -3

<h2>---------------------------</h2><h2>FOLLOW ME</h2>
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Read and write the number in two other forms 304,001
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Three hundred thousand four thousand one
300000 +4000+1
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3 years ago
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I NEED HELP QUICKLY!! Find the sum of the first 42 terms of the sequences (12, 16, 20, ....)
12345 [234]

Answer:

B

Step-by-step explanation:

Note the common difference between consecutive terms of the sequence.

d = 16 - 12 = 20 - 16 = 4

This indicates the sequence is arithmetic with sum to n terms

S_{n} = \frac{n}{2} [2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Here a₁ = 12 and d = 4, thus

S_{42} = \frac{42}{2} [ (2 × 12) + (41 × 4) ]

                          = 21( 24 + 164) = 21 × 188 = 3948 → B

7 0
3 years ago
The second step in the process for factoring the trinomial x2-5x-36 is to
Ivanshal [37]
X²-5x-36

Write -5x as a sum or difference.

x²+4x-9x-36

Factor out x from the expression.

x(x+4)-9(x+4)

Factor out x+4 from the expression.

(x+4)(x-9)

Answer: The second step is to factor out x.
8 0
4 years ago
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There are 4 cards in the box with the numbers 2, 5, 6, and 8. Two cards are drawn one after the other. The second card drawn is
malfutka [58]

It is given that there are 4 cards with numbers 2, 5, 6, and 8.

1) It is required to list all the numbers available when two cards are drawn one after the other and the second card is placed at the right of the first card drawn.

To do this, find the sample space of the draw which are:

25,26,28,52,56,58,62,65,68,82,85,86

Hence, the required numbers.

2) Recall that probability is the ratio:

Probability=\frac{\text{ number of favorable outcomes}}{\text{ total number of possible outcomes}}

From the numbers listed, notice that the total number of possible outcomes is 12.

Since event A is "obtained number is even", notice that the number of even numbers in the listed numbers is 9 (26,28,52,56,58,62,68,82,86).

Hence, the number of favorable outcomes is 9.

Substituting into the probability ratio gives the required probability:

P(A)=\frac{9}{12}=\frac{3}{4}

Check the number of numbers that are a multiple of 5, notice that they are 3 (25,65,85).

Hence, the required probability of event B is:

P(B)=\frac{3}{12}=\frac{1}{4}

The number of multiple of 3 in the listed numbers is 0 since there is no number that is a multiple of 3.

Hence, the required probability of event C is:

P(C)=\frac{0}{12}=0

Answers:

1) {25,26,28,52,56,58,62,65,68,82,85,86}

2) P(A) = 3/4

P(B) = 1/4

P(C)= 0

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