Enter an elgebraic expression

Mathematics

2 answers:

Serhud [2]3 years ago

5 0

Answer:

Umm...?? 2x + 3y - c ??

Step-by-step explanation:

DIA [1.3K]3 years ago

3 0

4x - -6y heheheheheheeh

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ANEK [815]

9514 1404 393

Answer:

x > -5

Step-by-step explanation:

(2/5)(x -1) < (3/5)(x +1) . . . . . given

2(x -1) < 3(x +1) . . . . . . . . . . .multiply by 5

2x -2 < 3x +3 . . . . . . . . . . . eliminate parentheses

-5 < x . . . . . . . . . . . . . . . . . . add -2x-3 to both sides

This matches the second answer choice: x > -5.

6 0

3 years ago

The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:

deff fn [24]

Step-by-step explanation:

Given equation of circle is,

${x}^{2} + {y}^{2} - 6y - 12 = 0 \\ by \: compairing \: it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f= - 6 \\ or \: f= - 3 \\ c = - 12$

again the another form of circle is,

${x}^{2} + {(y - k)}^{2} = 21 \\ or \: {x}^{2} + {y}^{2} - 2ky + {k}^{2} - 21 = 0 \\ by \: compairing \:it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\ g = 0 \\f = - k \\ c = {k}^{2} - 21$