All categories

3 years ago

Math Skip count by tens and fill in the missing numbers. 550, 660 570, 580, 590, 610,

Mathematics

1 answer:

irinina [24]3 years ago

4 0

Answer:

560, 600, 620, 630, 640, 650

Step-by-step explanation:

Just counted from 10, I guess.

You might be interested in

Determine a medida do ângulo indicado 14x-3=13x+1

iren2701 [21]

Solve for <span>x </span>by simplifying both sides of the equation, then isolating the variable.<span>x=4</span>

6 0

3 years ago

Clarisa's annual gross pay as an account manager is $54,000. If the graduated state tax rate is 1% for the first $5,000 and 3% f

Hoochie [10]

Answer:

Total taxes = $1,520

Step-by-step explanation:

We have two separate calculations for the taxes:

The tax rate for the first $5,000 of Clarisa's gross pay is 1%, so the amount of tax paid in this case is

1% * 5000 = $50

The tax rate for the amount of value over $5,000 (that is, 54,000 - 5,000 = 49,000) is 3%, so the amount of tax is:

3% * 49,000 = $1,470

So, the total amount deducted for state taxes is:

Total taxes = 50 + 1470 = $1,520

4 0

3 years ago

What is the value of 3-2

kicyunya [14]

Answer:

Step-by-step explanation:

brainliest pls if this helps

4 0

3 years ago

HELLO! looking for friends to talk to BUT this is a school website so imma put a question here, you can answer it if u want to b

yanalaym [24]

Answer:

(7.5, 1.2) and (7.5, -2.3)

8 0

3 years ago

A spherical balloon is being inflated at a rate of 3 cubic inches per second. Determine the change in the rate of the radius.How

Novay_Z [31]

Answer:

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

The radius is changing more rapidly when the diameter is 12 inches.

Step-by-step explanation:

Consider the provided information.

A spherical balloon is being inflated at a rate of 3 cubic inches per second.

The volume of sphere is $V=\frac{4}{3}\pi r^3$

Differentiate the above formula with respect to time.

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

Substitute the respective values in the above formula,

$3=4\pi 6^2\frac{dr}{dt}$

$\frac{1}{48\pi}=\frac{dr}{dt}$

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

When d=16

$3=4\pi 8^2\frac{dr}{dt}$

$\frac{3}{256\pi}=\frac{dr}{dt}$

Thus, the radius is changing more rapidly when the diameter is 12 inches.

5 0

3 years ago