Multiples of 3 plus 1 remainder are:
3n+1
Multiples of 4 plus 1 remainder are:
4n+1
Since these multiples must be the same number must be a multiple of 12 plus a remainder of one, which is:
12n+1
And the smallest such three digit number is:
12n+1>99 subtract 1 from both sides
12n>98 divide both sides by 12
n>8.17
Since n must be an integer, n=9
So then number is 12n+1
12(9)+1=109
Answer:
EF = 6
Step-by-step explanation:
Using the secant- secant power theorem, that is
GF × GE = GH × GS
4(4 + 2x) = 5(5 + x) ← distribute both sides
16 + 8x = 25 + 5x ( subtract 5x from both sides )
16 + 3x = 25 ( subtract 16 from both sides )
3x = 9 ( divide both sides by 3 )
x = 3
Then
EF = 2x = 2 × 3 = 6
Answer:
All integers that are below 0 is -1, -4, -2, -8, and -7.
At the moment it’s in standard form. We can easily turn this into slope int form (y= mx + b) tho
3y= -18x -18
y= -6x - 6
The answer is A that’s the answer
