The power of the man is 233.33 W
We'll begin by calculating the energy used by the man. This can be obtained as follow:
Mass (m) = 35 Kg
Height (h) = 0.50 m
Acceleration due to gravity (g) = 10 m/s²
<h3>Energy (E) =? </h3>
<h3>E = mgh </h3>
E = 35 × 10 × 0.5
<h3>E = 175 J</h3>
Thus the man used 175 J of energy.
Finally, we shall determine the power. This can be obtained as follow:
Energy (E) = 175 J
Time (t) = 0.75 s
<h3>Power (P) =? </h3>
<h3>Power = Energy / time </h3>
Power = 175 / 0.75
<h3>Power = 233.33 W </h3>
Therefore, the power of the man is 233.33 W
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Y=3x-4
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Answer:
Step-by-step explanation:
The relevant relations here are ...
- the sum of arc measures in a semicircle is 180°
- the sum of angles in a triangle is 180°
<h3>Arc measures</h3>
The given arc CD is part of the semicircular arc CDA. The remaining arc, DA, is the supplement of CD:
arc DA = 180° -CD = 180° -125° = 55°
Central angle AOD has the same measure, 55°. That is one of the acute angles in right triangle AOB, so the other one is the complement of 55°.
∠ABO = 90° -∠AOB = 90° -55°
∠ABO = 35°
<h3>Triangle angles</h3>
In right triangle ABC, angle ABC is given as 55°. The other acute angle, ACB, will be the complement of this.
∠ACB = 90° -∠ABC = 90° -55°
∠ACB = 35°
In the figure, angles ABO and ACB have measures of 35°.
Answer:
A
Step-by-step explanation:
it is A
F (x)= (x+1)(x-1)(x^2-2x-2)