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2 years ago

Look at the picture below and answer the question that is being asked

Mathematics

2 answers:

77julia77 [94]2 years ago

5 0

Answer:

Step-by-step explanation:

because they are telling you that the 7th graders were randomly chosen out of everyone who rides in a car to school to be fractioned out.

IrinaVladis [17]2 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

5/6 – 6/12<br><br>I am lost bc I'm not a math person so pls help me?

vovangra [49]

First, we must find the common denominator (12) ✵

10/12-6/12 ✵ ✵ ✵ ✵

Now, why 10? ✵ ✵ ✵

Because we CAN'T just take the denominator and change it; we must change both the denominator AND the numerator:

✵ • - ○

4/12 ✧ ✩ ✶ ✺ ✱

We can simplify, or reduce, this fraction: ✱ ✱

1/3 ✩ ✦ ✤

I hope it helps!

$*VirtuosoTeen*$

7 0

3 years ago

Read 2 more answers

Assuming log, 4.4 = 1.4816 and log 7.7 = 2.0142, then whats the value of log, 7/4

denis23 [38]

Log (7/4) is equivalent to log (7.7/4.4), therefore it's log(7.7) - log(4.4), or...

2.0142 - 1.4816 = 0.5326

4 0

2 years ago

Read 2 more answers

For lunch, you get tacos that cost $5.50. You also get chips and salsa for $3.99. What is the total cost of your lunch?

ollegr [7]

Answer:

9.49

Step-by-step explanation:

Add the price of the chips and salsa to the price of the tacos

5.50

+3.99

---------------

9.49

3 0

2 years ago

Read 2 more answers

A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a

kkurt [141]

Answer:

$b=h=\sqrt{6}$ m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box= $2b^2+4bh$

$2b^2+4bh=36$

$b^2+2bh=18$

$2bh=18-b^2$

$h=\frac{18-b^2}{2b}$

Volume of box, V= $b^2h$

Substitute the values

$V=b^2\times \frac{18-b^2}{2b}$

$V=\frac{1}{2}(18b-b^3)$

Differentiate w. r.t b

$\frac{dV}{db}=\frac{1}{2}(18-3b^2)$

$\frac{dV}{db}=0$

$\frac{1}{2}(18-3b^2)=0$

$\implies 18-3b^2=0$

$\implies 3b^2=18$

$b^2=6$

$b=\pm \sqrt{6}$

$b=\sqrt{6}$

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

$\frac{d^2V}{db^2}=-3b$

At $b=\sqrt{6}$

$\frac{d^2V}{db^2}=-3\sqrt{6}$

Hence, the volume of box is maximum at $b=\sqrt{6}$ .

$h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}$

$h=\frac{18-6}{2\sqrt{6}}$

$h=\frac{12}{2\sqrt{6}}$

$h=\sqrt{6}$

$b=h=\sqrt{6}$ m

7 0

3 years ago

A cooking show currently has about 223,00 regular viewers. The number of regular viewers has been decreasing at a rate of 4.7% p

Mazyrski [523]

The best prediction for the number of regular spectators that the program will have in 6 years is obtained with the following formula:
Pf = Po×(1-b) ^ t
Where:
Pf = final population
Po = initial population
b = decrease rate
t = timpo in years
So:
Pf = 223.00×(1-0.047) ^ 6
Pf = 167,056
The answer is the last option.

5 0

2 years ago