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madreJ [45]
3 years ago
15

a film canister in the shape of a cylinder has a height of 8 centimeters and a volume of the film canister. write an equation fo

r the volume of the film canister.
Mathematics
1 answer:
uranmaximum [27]3 years ago
8 0

Answer:

Part a) The equation for the volume of the film canister is

32\pi=\pi r^{2}(8)

Part b) The radius of the film canister is 2\ cm

Step-by-step explanation:

<u><em>The complete question is</em></u>

A film canister in the shape of a cylinder has a height of  8 centimeters and a volume of 32π cubic centimeters.

a. Write an equation for the volume of the film canister.

b. What is the radius of the film canister?

Part a) Write an equation for the volume of the film canister

we know that

The volume of a cylinder is equal to

V=\pi r^{2} h

where

r is the radius of the circular base

h is the height of the cylinder

we have

V=32\pi\ cm^3

h=8\ cm

substitute

32\pi=\pi r^{2}(8) ----> equation for the volume of the film canister

Part b) What is the radius of the film canister?

we have

32\pi=\pi r^{2}(8)

32\pi=8\pi r^{2}

Simplify

Divide by 8π both sides

4=r^{2}

square root both sides

r=2\ cm

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A couple plans to have children until they get a​ girl, but they agree they will not have more than three​ children, even if all
barxatty [35]

Answer:

a)Let X be number of children

X=1,2,3

P(X=1)= 0.47

P(X=2) = 0.2491

P(X=3) = 0.942923

b) 3.7970

c) 1.6232

Step-by-step explanation:

The complete question is:

A couple plans to have children until they get a​ girl, but they agree they will not have more than three​ children, even if all are boys. Assume that the probability of having a girl is 47.00​%. ​

a) Create a probability model for the number of children​ they'll have.

X=1,2,3

​P(X=1)=??

P(X=2)= ??

P(X=30=???

​(Round to four decimal places as​ needed

​b) Find the expected number of children.

E(X)= ???

​c) Find the expected number of boys​ they'll have.

Expected number of boys= ???

Solution:

Probability of a girl= 0.47

Probability of a boy= 0.53

a) P(X=1)= 0.47

P(X=2) = 0.47× 0.53= 0.2491

P(X=3)= 0.47× 0.53× 0.53 + 0.53× 0.53× 0.53

             = 0.942923

b) E(number of children)= 1× P(X=1) + 2 ×P(X=2) + 3 × (PX=3)

                                       = 3.796969

c) Y: number of boys

P(Y=1)= 0.53×0.47= 0.2491

P(Y=2) = 0.53×0.53×0.47=0.46375

P(Y=3)= 0.53× 0.53× 0.53= 0.148875

E(Y)= P(Y=1)×1 + P(Y=2)×2 + P(Y=3)×3

       = 0.148875×3 +0.46375×2+0.2491 ×1

      = 1.6232

5 0
3 years ago
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