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ElenaW [278]
3 years ago
8

Helppppppppppppppppppppppppppppppppppppp

Mathematics
2 answers:
andrew-mc [135]3 years ago
7 0
The equation would be y = -5/4x + 3.

To find slope you would use the slope formula of (y2-y1)/(x2-x1). This gives us the slope of -5/4. Then we find the y-intercept. When looking on the graph we see the only y intercept is the point (0,3), so we get the number 3.
torisob [31]3 years ago
6 0

Answer:

1.25X+3

Step-by-step explanation:

(-4,8) AND (4,-2)

Rise

-------

Run

<u>8+2 =  10</u>

-4-4=  -8

1.25

from the y intercept 0, the line is a 3, (0,3)

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The mean grade in Mathematics of Grade 11 students from school A is 83 with standard deviation of 4, while the mean grade in Mat
Ulleksa [173]

Using the context surrounding the word trough in line 9 of "Concrete Mixers," explain what a trough looks like and what it does on a concrete mixer. .

sorry I can't delete it this not answer your question

7 0
3 years ago
The sum of the angle measures of any triangle is 180 degrees. Suppose that one angle in a triangle has a degree measure of −7x10
katrin [286]
Third Angle = 180- (-70+-8) -----> Third Angle = 102
3 0
3 years ago
Is the equation 2x + 5 = 1 true, false, or open? Explain.
4vir4ik [10]

Answer:

open

Step-by-step explanation:

beacause

2x+5=1

2x=1-5

2x=-4

x=-4/2

x-2 so its open

6 0
3 years ago
7 measured data points have a sample mean of 1403 and a standard deviation of 27. Determine the best estimate of the mean value
mina [271]

Answer:

Step-by-step explanation:

Hello!

You have sample of n=7 with mean X[bar]= 1403 and standard deviation S=27 and are required to estimate the mean with a 95%CI.

Asuming this sample comes from a normal population I'll use a stuent t to estimate the interval (a sample of 7 units is too small for the standard normal to be accurate for the estimation):

[X[bar]±t_{n-1;1-\alpha /2} * \frac{S}{\sqrt{n} }]

t_{n-1;1-\alpha /2} = t_{6;0.975}= 2.365

[1403±2.365*\frac{27}{\sqrt{7} }]

[1378.87;1427.13]

The margin of error is the semiamplitude of the interval and you can calculate it as:

d= \frac{Upbond-Lowbond}{2}= \frac{1427.13-1378.87}{2} = 24.13

With a confidence level of 95% you'd expect that the real value of the mean is contained by the interval [1378.87;1427.13], the best estimate of the mean value is expected to be ± 24.13 of 1403.

I hope it helps!

4 0
3 years ago
Help pleasseeeee !! :)))))) i’ll give brainliest
Elis [28]

Answer:

I think It's alternative exterior

5 0
3 years ago
Read 2 more answers
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