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konstantin123 [22]
3 years ago
12

John mows 247 square feet of lawn per minute. how many square yards of lawn does he mow per hour?

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0
1647. 1 hour=60 minutes. John can mow 247 square feet per minute, so he can mow 60*247=14820 square feet per hour. 1 yard=3 feet, so 1 square yard =3^2=9 square feet, so in the same duration of time, John can mow 14820/9=1647 square yards (approximately) per hour. 
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6^4 * 6^4

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Answer:

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x/12 = -11

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natita [175]

Lyra's speed of travel is 6.71 feet per seconds and Lyra's direction of travel is 27 degrees north of east

<h3>How to determine the speed of travel?</h3>

The diagram that represents the scenario is added as an attachment.

Let x represents Lyra's speed of travel.

The value of x is calculated using the following Pythagoras theorem.

x = \sqrt{3^2 + 6^2}

Evaluate the exponents

x = \sqrt{9 + 36}

Evaluate the sum

x = \sqrt{45}

Evaluate the exponent

x = 6.71

Hence, Lyra's speed of travel is 6.71 feet per seconds

<h3>How to determine the direction of travel?</h3>

The direction (∅) is calculated using the following tangent ratio.

\tan(\theta) = \frac 36

Evaluate the quotient

\tan(\theta) = 0.5

Take the arc tan of both sides

\theta = \tan^{_1}(0.5)

Evaluate

\theta = 27

Hence, Lyra's direction of travel is 27 degrees north of east

Read more about speed and distance at:

brainly.com/question/4931057

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3 0
1 year ago
For each of the following, determine the interest rate per compounding period. 1) 12% per year, compounded weekly b) 8% per year
Zarrin [17]

Using compound interest, the rates per compounding period are given as follows:

a) 0.1273 = 12.73%.

b) 0.0833 = 8.33%

c) 0.0617 = 6.17%

<h3>What is compound interest?</h3>

The amount of money earned, in compound interest, after t years, is given by:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

In which:

  • A(t) is the amount of money after t years.
  • P is the principal(the initial sum of money).
  • r is the interest rate(as a decimal value).
  • n is the number of times that interest is compounded per year.

The <u>interest rate per compounding period</u> is given as follows:

\left(1 + \frac{r}{n}\right)^n - 1

For item a, the parameters are:

r = 0.12, n = 52.

Hence:

\left(1 + \frac{0.12}{52}\right)^{52} - 1 = 0.1273

For item b, the parameters are:

r = 0.08, n = 104.

Hence:

\left(1 + \frac{0.08}{104}\right)^{104} - 1 = 0.0833

For item c, the parameters are:

r = 0.06, n = 12.

Hence:

\left(1 + \frac{0.06}{12}\right)^{12} - 1 = 0.0617

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