9.54

what are the factors of 47 (cuz im STUPID and i dont feel like doing this cuz im working on geogrophy)

Hitman42 [59]

Hey there! I'm happy to help!

The factors are the numbers you multiply to get 47. And they can't be fractions or numbers with fractions. They have to be integers (numbers without fractions).

So far, we see that we can multiply 1 and 47 to get 47. To see if there are any more, we see what numbers 1-10 we can divide by.

We cannot divide by 2 because 47 is odd.

We cannot divide by 3 because it gives us 15.6666...

We can't divide by 4 because 47 is odd.

We can't divide by 5 because 47 does not have a 5 or 0 in the ones place.

We can't divide by 6 because 47 is odd.

We can't divide by 7 because it gives us 6.714285....

We can't divide by 8 because 47 is odd.

We can't divide by 9 because it gives us 5.2222

And we obviously can't divide it by 10.

Therefore, the factors of 47 are 1 and 47. A number whose only factors are 1 and itself is called a prime number.

I hope that this helps! Have a wonderful day! :D

3 0

3 years ago

Read 2 more answers

Five thousand raffle tickets are sold for $5 each. 50 winnings numbers will be chosen, 40 of which will win $100 each and 10 of

Allisa [31]

Answer:

Step-by-step explanation:

Given

there are 50 winning number out of which 40 get $ 100 each and 10 wins $ 1000 .

let x denotes the winning from a randomly selected ticket

$x=100\ with\ Probability\ \frac{40}{5000}$

$x=1000\ with\ Probability\ \frac{10}{5000}$

Expected value is given by

$E(x)=100\times \frac{40}{5000}+1000\times \frac{10}{5000}$

$E(x)=0.8+2=2.8$

and Expected return is given by

$=100\times \frac{40}{5000}+1000\times \frac{10}{5000}-5$

$=2.8-5=$ -2.2$

5 0

2 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

7 0

2 years ago

Read 2 more answers

Please click here and help me

Alex17521 [72]

Answer:

A. ∠AOD = 170°

Step-by-step explanation:

103° + 55° + 12° = 170°

6 0

2 years ago

Which of the following fractions will convert to terminating decimals? A.5/6

dexar [7]

Answer:

answer E

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers