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3 years ago

Whoever answers these gets brainlist and 29 points.

Mathematics

2 answers:

Oksana_A [137]3 years ago

4 0

Answer:

1)1/15

2)3/10

3)1/6

4)3/10

Step-by-step explanation:

pls give me brainliest and i hope im right!

Assoli18 [71]3 years ago

3 0

Answer: 1. 1/15

2. 3/10

3. 1/6

4. 3/10

Step-by-step explanation:

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Diane has a temperature of 99°F. What is her temperature in Celsius?

xenn [34]

Answer:

$37.\bar{2}\textdegree C$

Step-by-step explanation:

The formula for converting °F to °C is:

$(\textdegree F -32) \frac{5}{9}=\textdegree C$

We are given the temperature of 99°F.

=====================================

$(99\textdegree F -32) \frac{5}{9}=\textdegree C\\\rule{150}{0.5}\\(67) \frac{5}{9}= \textdegree C\\\\\boxed{37.\bar{2} = \textdegree C}$

=====================================

Diane's temperature in Celsius is 37.22...°C.

The 2 is recurring.

=====================================

Hope this helps!

8 0

3 years ago

For the following exercises, determine whether each of the following relations is a function.

irina1246 [14]

Answer:

The relation y=2x+8 is a function because the two different output values of the function have the one unique input value.

Step-by-step explanation:

The given relation is y=2x+8.

It is required to determine the relation is a function.

This solution can be obtained by using the concept of function. First write the given relation y=2x+8 and determine whether the given relation is a function.

Step 1 of 1

The given relation is y=2x+8.

This relation shows that the two different output values of the function have one unique input value and this relation is a linear function.

Hence, the relation is a function.

3 0

2 years ago

Describe the graph represented by the equation r=5/(3+2 sin theta).

Yuki888 [10]

We have the following equation:

$r= \frac{5}{3+2sin(\theta)}$

If we graph this equation we realize that in fact this is an ellipse with major axis matching the y-axis. So we can recognize these characteristics:

1. Center of the ellipse:

The midpoint C of the line segment joining the foci is called the center of the ellipse. So in this exercise this point is as follows:

$C(0, -2)$

2. Length of major axis:

The line through the foci is called the major axis, so in the figure if you go from -5, at the y-coordinate, and walk through this major axis to the coordinate 1, the distance you run is the length of the major axis, that is:

$6 \ units$

3. Length of minor axis:

The line perpendicular to the foci through the center is called the minor axis. So in the figure if you go from -2, at the x-coordinate, and walk through this minor axis to the coordinate 2, the distance you run is the length of the minor axis, that is:

$4 \ units$

4. Foci:

Let's find c as follows:

$c=\sqrt{a^{2}-b^{2}}=\sqrt{3^{2}-2^{2}}=\sqrt{5}$

Then the foci are:

$f_{1}=(0, \sqrt{5}-2)$

$f_{2}=(0, -\sqrt{5}-2)$