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Len [333]
3 years ago
5

Draw a graph of the linear equations x – 4y + 10 = 0 and x + 4y – 10 = 0. Find the coordinates of the vertices of the triangle f

ormed by these lines along with the X-axis
Mathematics
2 answers:
Lina20 [59]3 years ago
6 0
The first equation crosses the x axis at x - 4 x 0 + 10 = 0 => x = -10

The second equation crosses the x axis at x + 4 x 0 - 10 = 0 => x = +10

Adding the equations together gives 2x = 0 => x = 0
0 + 4y - 10 = 0 => 4y = 10 => y = 2.5

The vertices of the triangle formed by the two lines and the x axis are (-10, 0) (10, 0) and (0, 2.5)
Licemer1 [7]3 years ago
3 0

Step-by-step explanation:

<em><u>x-14y</u></em><em><u>=</u></em><em><u>0</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>x</u></em><em><u>=</u></em><em><u>0</u></em><em><u>/</u></em><em><u>1</u></em><em><u>4</u></em><em><u>y</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>x</u></em><em><u>=</u></em><em><u>1</u></em><em><u>4</u></em><em><u>y</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>1</u></em><em><u>4</u></em><em><u>y</u></em><em><u> </u></em>

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Artist 52 [7]

AE x BE = DE x CE

6x5 = 30

6 x DE = 30

DE = 30/6 =5

DC = DE +CE = 5+6 =11

Answer is C) 11

8 0
3 years ago
P<br> __ =6<br><br> 5<br> What does P mean?
Yuri [45]
To find (P) you turn the fraction into an imoroper fraction 

5x6 =30  

30/5 =6 
p=30 
  
Ps this is easy if your memerized your muliplacation 

5 0
3 years ago
Please help me find out the process to find y for the first three questions and tell me what y is
Sliva [168]

Answer:

1. y = 14.718

2. ??

3. y = 39.794°

Step-by-step explanation:

<em>HINT the side we already know and the side we are trying to find, we use the first letters of their names and the phrase "SOHCAHTOA" to decide which function: </em>

SOH...

 Sine: sin(θ) = Opposite / Hypotenuse

...CAH...

 Cosine: cos(θ) = Adjacent / Hypotenuse

...TOA

 Tangent: tan(θ) = Opposite / Adjacent

1. Sine: sin(θ) = Opposite / Hypotenuse

sin(42°) = y / 22

so on your calculator enter 42 then sin = 0.669

0.669 = y/22      multiply both sides by 22 to get y

y = 14.718

2. is there any other information??

3. The two sides we know are Opposite 40 and Adjacent 48.

SOHCAHTOA tells us we must use Tangent.

Calculate Opposite/Adjacent = 40/48 = 0.833

Find the angle from your calculator using tan-1

Tan y° = opposite/adjacent = 40/48 = 0.833  

tan-1 of 0.833 = 39.794°

7 0
3 years ago
I need help and NOW PLEASE
mixas84 [53]

Answer:

a) 7/4 b) 15/2

Step-by-step explanation:

a) Scale Factor = Image / Object

Take the side of Triangle ABC that's BC Why? Because it corresponds with the Image Triangle ADE's DE

= 21/12 = 7/4

b) 7/4 = 10+ x / 10

Cross Multiply

= 4 ( 10 + x ) = 70

= 40 + 4x = 70

= 4x = 70-40

= 4x = 30

= 4x/4 = 30/4

x = 15/2

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