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SIZIF [17.4K]
3 years ago
12

The growth rate of some species of bamboo is 0.0000237 miles per hour. write this in scientific notation

Mathematics
1 answer:
Tanzania [10]3 years ago
4 0

Answer:

2.37 x 10 ^ -5

Step-by-step explanation:

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7 - 14x = 2x - 5<br> This is hard
gizmo_the_mogwai [7]

Answer:

3/4 = x

Step-by-step explanation:

7 - 14x = 2x - 5

+14x    +14x

_____________

7 =16x -5

+5     +5

__________-

12 = 16x

÷16   ÷16

__________

12/16 = x

-or-

3/4 = x

Hope this helped :D

6 0
3 years ago
Read 2 more answers
What is the product?
cupoosta [38]

Answer:

The first one, 10 15 20

                      45 -5 -35

                      55 25 -15

Step-by-step explanation:

7 0
3 years ago
How do I solve this equation?
Keith_Richards [23]

Answer:

y=\frac{7}{2}x+11

Step-by-step explanation:

To solve, we need to find the y-intercept (b). In order to find the y-intercept, we can plug in the slope and the (x,y) coordinate pair given to us into the equation to solve for the y-intercept:

y=mx+b

4=(-7/-2)*-2+b

4=14/-2+b

4=-7+b

Add 7 to both sides

b=11

Therefore the equation is:

y=\frac{7}{2}x+11 (note that the fraction is positive since the two negatives cancel out)

4 0
3 years ago
For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

  • Divide row 1 by 2 \left(R_1=\frac{R_1}{2}\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

  • Divide row 3 by −19 \left(R_3=\frac{R_3}{-19}\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

  • Subtract row 3 multiplied by 16 from row 1 \left(R_1=R_1-\left(16\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]

  • Add row 3 multiplied by 6 to row 2 \left(R_2=R_2+\left(6\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

8 0
3 years ago
Write down the equation of a straight line that is parallel to y = 4x+2
ELEN [110]

Answer:

y = 4x + 5

Step-by-step explanation:

anything with the slope of 4x is parallel to the given equation. therefore, there are an infinite amount of answers.

<u>so, y = 4x + any number</u>

hope this helps!<3

4 0
3 years ago
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