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Ostrovityanka [42]
3 years ago
7

the measures of the angles of a triangle are shown in the figure below. find the measure of the smallest angle ​

Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0

Explanation is in the file

tinyurl.com/wtjfavyw

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PLEASE HELP WITH THIS QUESTION
DedPeter [7]

I think the correct answer is c

3 0
3 years ago
PLEASE HELP ME I AM HORRIBLE AT TRIGONOMETRY!!! TRIANGLES ARE SO HARD!!!
OleMash [197]

Answer:

A construction worker may use trigonometry when building the roof of a house. They may have to calculate the right angle that hypotenuse must sit at so water doesn't build up on the roof and cause leaks.

(this may be more of an architect's job, as they are the ones that design the houses)

or

An air traffic controller may use trigonometry to find how long it will take an airplane to land/how far the airplane is from the ground while it is in the sky (hypotenuse), based on its height from the ground (opposite) and the distance away from the runway it is (adjacent). They can also calculate the angle of elevation of the airplane from the tower they work in.

8 0
3 years ago
4x-11y=68 ; 6x+5y=-27 by elimination
zimovet [89]

Answer:

x=\frac{1}{2}\\\\y=-6

Step-by-step explanation:

Given the following system of equations:

\left \{ {{4x-11y=68} \atop {6x+5y=-27}} \right.

In order to solve the system of equations using the Elimination Method, you can follow these steps:

- Multiply the first equation by -6 and the secondd equation by 4.

- Add both equations.

- Solve for "y".

Then:

\left \{ {{-24x+66y=-408} \atop {24x+20y=-108}} \right\\.........................\\86y=300\\\\y=\frac{-516}{86}\\\\y=-6

- Substitute the value of "y" into one of the original equations and solve for "x":

6x+5(-6)=-27\\\\6x=-27+30\\\\x=\frac{3}{6}\\\\x=\frac{1}{2}

4 0
3 years ago
Which equation is the Slope - intercept form
Ulleksa [173]
It's A. Y=mx+b hope this helps
5 0
2 years ago
Read 2 more answers
To three decimal places, find the average value of f(x) = 2x2 + 3 on the interval [0, 2].
salantis [7]
The formula for the average value of a function is \frac{1}{b-a}  \int\limits^b_a {f(x)} \, dx where b is the upper bound and a is the lower.  For us, this formula will be filled in accordingly.  \frac{1}{2}  \int\limits^2_0 {(2x^2+3)} \, dx.  We will integrate that now: \frac{1}{2}[ \frac{2x^3}{3}+3x] from 0 to 2.  Filling in our upper and lower bounds we have \frac{1}{2}[( \frac{2(2^3)}{3}+3(2))-0] which simplifies to \frac{1}{2}( \frac{16}{3}+6) and \frac{1}{2}( \frac{16}{3}+ \frac{18}{3})= \frac{1}{2}( \frac{34}{3}) which is 17/3 or 5.667
7 0
3 years ago
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