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SIZIF [17.4K]
3 years ago
13

ASAP!! please help :( 40 POINTS​

Mathematics
1 answer:
Ad libitum [116K]3 years ago
6 0

Answer:

x ≥ 4

Step-by-step explanation:

-4(8 - 3x) ≥ 6x - 8

-32 + 12x ≥ 6x - 8

-32 + 8 ≥ 6x - 12x

-24 ≥ -6x

x ≥ 24 / 6

x ≥ 4

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Pls help with this one I will give brainliest thank you! Number 5
melamori03 [73]

Answer:

The volume of the fish tank is 48000 cubic centi meter.

Step-by-step explanation:

The volume of a Cuboid is l*b*h (length*breadth*height)

Here,

length(l) =60 cm

breadth(b)= 20 cm

height(h)=40 cm

Volume=l*b*h

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Volume= 48000 cubic centimeter

5 0
3 years ago
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Maria is m inches tall. Blaire is 2 inches taller than Maria. If Blaire is 52 inches tall, which equation could be used to find
Setler79 [48]
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A circus tent is cylindrical upto a height of 3.3 m and conical above it if the diameter of the base is 100m and slant height of
Rina8888 [55]

Total cost of canvas required in making the tent is rupees 79128

<em><u>Solution: </u></em>

Given:

Height of the cylindrical tent = h = 3.3 m

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radius = \frac{diameter}{2} = \frac{100}{2} = 50

r = 50 m

<em><u>Curved surface area of cylinder:</u></em>

C.S.A = 2 \pi rh

C.S.A = 2 \times 3.14 \times 50 \times 3.3 = 1036.2

Thus Curved surface area of cylinder = 1036.2 square meter

<em><u>Curved surface area of cone:</u></em>

C.S.A = \pi rl

C.S.A = 3.14 \times 50 \times 56.4 = 8854.8

Thus Curved surface area of cone = 8854.8 square meter

<em><u>Total curved area of tent:</u></em>

⇒ curved area of cone + curved area of cylinder

\rightarrow 8854.8 + 1036.2=9891

Thus total curved area of tent = 9891 square meter

<em><u>find total cost of canvas required in making the tent:</u></em>

The cost of canvas is 8 rupees per square meter

\rightarrow \text{total cost } = 9891 \times 8 = 79128

Thus total cost of canvas required in making the tent is rupees 79128

7 0
3 years ago
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3 years ago
May someone please help me?
kvv77 [185]

Answer:

the answer is ac line segment

6 0
4 years ago
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