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Oduvanchick [21]
4 years ago
9

Someone help me with this question please it would help me a lot !!!

Mathematics
1 answer:
motikmotik4 years ago
3 0

Answer:

x intercept ( -40,0)

y intercept ( 0,15)

Step-by-step explanation:

The x intercept is where it crosses the x axis.  The y value is zero

(-40,0)

The y intercept is where it crosses the y axis.  The x value is zero

(0,15)

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Can you halp me pls it really hard pls pls pls help me
zysi [14]
Question 1: this is simple adding
do the fractions first 1/4 + 3/4 = 4/4 or 1
then the whole numbers 1+1+1=3 gallons

Question 2: do it the same as the first you can make 1 1/2 into a mixed number which is 3/2 and make 4 into 8/2 then subtract 8/2 - 5/2= 3/2 or 1 1/2

Question 3: make into mixed numbers 5/3+5/3= 10/3 or 3 1/3
6 0
4 years ago
Read 2 more answers
Raoul bought 9 bags of granola mix. Each bag cost $5.59.<br><br> How much did Raoul spend?
IRINA_888 [86]

Answer:

$50.31

Step-by-step explanation:

9x5.59=50.31

An easy way to do it is take out the decimals and multiply. Then add the decimals by seeing how many places in 5.59 (2) and move the decimal 2 times on your answer.

7 0
3 years ago
The product of 5 and x, increased by 6
Naily [24]

Answer:

30

Step-by-step explanation:

6*5=30 5 and 6 are products

8 0
3 years ago
Q. Unscramble the following term related to algebra:- ROTPORAE.​
ASHA 777 [7]

Answer:

operator

Step-by-step explanation:

Operator is represented as any symbol that indicates an operation to be performed.

Examples:

- Square root of√x, which indicates the square root is to be taken

- d/dx, which indicates differentiation with respect to x is to be performed

4 0
2 years ago
Read 2 more answers
Two gears are both connected to the same belt. The smaller of the two gears has a radius of 4ft &amp; the larger of the two gear
krek1111 [17]

Answer:

\omega_1 = \frac{5Rad}{3s} and \omega_2 = \frac{35Rad}{12s}

Step-by-step explanation:

Given that the larger gear is turning at the rate 50rpm. The angular velocity, \omega_1, of the larger gear can be calculated as follows:

\omega_1 = \frac{50rev}{m} to convert that to secs, we know that 1 rev = 2πRad and 60secs make a min, so we have:

\omega_1 = \frac{50rev}{m} \times \frac{2\pi Rad}{1rev} \times \frac{1m}{60s}

That gives

\omega_1 = \frac{100Rad}{60s}

Which gives:

\omega_1 = \frac{5Rad}{3s}

This is the angular velocity of the larger gear in rads/sec.

In order to get the angular velocity of the smaller gear, we know from the question that both gear are connected to the same belt. This implies that they have the same linear velocity. Thus let us find the linear velocity of the larger gear. This is given by

v = r_1 \times \omega_1 where v stands for linear velocity and r_1 for radius of larger velocity.

We are given the radius of the larger gear as 7ft so we have

v = 7ft \times \frac{5Rad}{3s} = \frac{35ft}{3s}

To get the angular velocity of the smaller gear, we use

v = r_2 \times \omega_2 where r_2 is the radius of the smaller gear which is given as 4.

Since linear velocity is the same, we have

\omega_2 = \frac{35ft}{4 \times 3s}

\omega_2 = \frac{35Rad}{12s}

5 0
3 years ago
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