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777dan777 [17]
3 years ago
11

IT'S URGENT PLEASEE What is the slope of a line perpendicular to the line 2y = 3x - 10?

Mathematics
2 answers:
sashaice [31]3 years ago
6 0
Perpendicular slope is -2/3
belka [17]3 years ago
5 0
<h3>Answer:  perpendicular slope is -2/3</h3>

=================================================

Work Shown:

Solve the given equation for y

2y = 3x - 10

y = (3x-10)/2 ..... divide both sides by 2

y = (3x)/2 - 10/2

y = (3/2)x - 5

The equation is in y = mx+b form with m = 3/2 as the slope.

The perpendicular slope is -2/3 because we flip the fraction and the sign from positive to negative.

Note how multiplying the original slope 3/2 and the perpendicular slope -2/3 leads to -1

(3/2)*(-2/3) = -1

This is true for any pair of perpendicular lines, assuming neither line is vertical.

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This was the question it got deleted I just need 1,2,5
scoundrel [369]

Answer:

1. The volume of the cylinder is 263 cm^{3}.

2. The volume of the cylinder is 12 m^{3}.

3. The volume of the cylinder is 3165.1 cm^{3}.

4. The radius of the cylinder is 3.6 cm.

5a. Area of the base is 50.2 cm^{2}.

5b. The curved surface area of the pencil holder is 351.7 cm^{2}.

5c. The surface are of the pencil holder is 452.2 cm^{2}.

Step-by-step explanation:

1. The given shape is a cylinder, so that;

volume of a cylinder = \pir^{2}h

                                  = 3.14 x (3.8)^{2} x 5.8

                                  = 262.98128

The volume of the cylinder is 263 cm^{3}.

2. This is also a cylinder, but with a given diameter.

radius = \frac{diameter}{2}

          = \frac{1.2}{2} = 0.6 m

volume of a cylinder = \pir^{2}h

                                  = 3.14 x (0.6)^{2} x 10.6

                                  = 11.98224

The volume of the cylinder is 12 m^{3}.

3. volume of a cylinder = \pir^{2}h

                                      = 3.14 x 6^{2} x 28

                                      = 3165.12

The volume of the cylinder is 3165.1 cm^{3}.

4. volume of a cylinder = \pir^{2}h

239 = 3.14 x r^{2} x 6

239 = 18.84 r^{2}

r^{2} = \frac{239}{18.84}

   = 12.6858

r = \sqrt{12.6858}

 = 3.5617

The radius of the cylinder is 3.6 cm.

5. Area of the base = \pir^{2}

radius = \frac{diameter}{2}

           = \frac{8}{2} = 4 cm

Area of the base = 3.14 x 4^{2}

                            = 50.24

Area of the base is 50.2 cm^{2}.

5b. Area of the curved surface of the pencil holder = 2\pirh

                                                                    = 2 x 3.14 x 4 x 14

                                                                     = 351.68

The curved surface area of the pencil holder is 351.7 cm^{2}.

5c. Surface area of the pencil holder = 2\pirh + 2\pir^{2}

                               = 2\pir(h + r)

                                = 2 x 3.14 x 4 (14 + 4)

                                = 452.16

The surface are of the pencil holder is 452.2 cm^{2}.

7 0
3 years ago
Solve the system y=x-3 y=-2x+3
vivado [14]

Answer:

x = 2, y= -1 Or (2, -1)

Step-by-step explanation:

Let’s solve the system using substitution. First we can set the equations equal to each other:

x-3= -2x +3

Now solve for x

3x-3= 3

3x = 6

x=2

Now that we have x, we can plug it back into one of the original equations to get y

y= x-3

y= 2-3

y = -1

Finally, the solution to the system of equations is (2, -1).

6 0
3 years ago
Read 2 more answers
Two square are congruent ,if they have same ______​
OverLord2011 [107]

Two squares are congruent if they have the same side length.

3 0
3 years ago
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Putt the fraction from grates to least value 1/2 5/6 3/4 1/3 1/6 1/4 2/3<br>​
gavmur [86]
1. 5/6
2. 3/4
3. 2/3
4. 1/6
5. 1/4
6. 1/2
7 0
3 years ago
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9. The endpoints of a diameter of a circle are A (2,1) and B(5,5). Find the area of the circle in terms of . (1 point)
Georgia [21]

Answer:

Area of the circle is 6.25π sq.unit

Step-by-step explanation:

The centre of the circle is at the mid point of a diameter. Th mid point of the diameter is at (5+22,5+12)or(72,3),which is centre. Radius is the distance from end point (5,5)to centre (72,3)∴r=√(5−72)2+(5−3)2=√1.52+4=√6.25=2.5∴

Area of the circle is Ac=π⋅r2=π⋅2.52=6.25π sq.unit[Ans]

5 0
3 years ago
Read 2 more answers
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