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2 years ago

Two bikers are riding a circular path.

Mathematics

2 answers:

kolbaska11 [484]2 years ago

8 0

<h2> $\huge \mathfrak \orange{Question}$ </h2>

Two bikers are riding a circular path.

The first rider completes a round in 12

minutes. The second rider completes

a round in 18 minutes. If they both

started at the same place and time

and go in the same direction, after

how many minutes will they meet

again at the starting point?

<h2> $\huge \mathfrak \orange{Solution}$ </h2>

$\huge \mathsf \blue{Given}$

First rider takes 12 minutes to complete a round.
Second rider takes 18 minutes to complete a round.

$\huge \mathsf \blue{To\: Find}$

After how many minutes will they meet

again at the starting point?

Take the LCM of 12 and 18

12 = 2 × 2 × 3

18 = 2 × 3 × 3

Thus, the LCM of 12 and 18 is 36.

<h3>So they will meet after 36 minutes again at the starting point.</h3>

Arturiano [62]2 years ago

7 0

Answer:

Find the LCM of 12 & 18 .

12 = 2×2×3

18 = 3×3 ×2

So , LCM of ( 12 , 18 ) = 2×3×2 = 36

<h2>Therefore he meet after 36 minutes at starting point..!!</h2>

<h2 /><h2>Hopefully u will satisfy with my answer of ur question..!!</h2>

<h2>Have a nice day ahead dear..!!</h2>

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Lorico [155]

Answer:

$a=502 +1.28*81=605.68$

So the value of height that separates the bottom 90% of data from the top 10% is 605.68.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(502,81)$

Where $\mu=502$ and $\sigma=81$

We want to find a value a, such that we satisfy this condition:

$P(X>a)=0.1$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

$P(X$