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3 years ago

Which of the following is ordered pair for point C?

Mathematics

2 answers:

Lunna [17]3 years ago

8 0

Answer:

B(4,2)

Step-by-step explanation:

as you can see that if want to find coordinates u should know that the position of x and y is (x,y). So u can that c on the x is lower than 5 so that u can say it is 4 and y is too far away from 5 also u it will be 2.

ASHA 777 [7]3 years ago

5 0

Answer:

B. (4,2)

Step-by-step explanation:

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Which polynomial is the perfect square trinomial? And why??? Help Please!!

lutik1710 [3]

<h3>Answer:</h3>

See the attached

<h3>Step-by-step explanation:</h3>

When you square the binomial (a -b), you get ...

... (a -b)² = a² -2ab +b²

That is, both the a² and b² terms have positive signs, and the middle term is twice the product of the roots of the squared terms.

The last two selections have negative signs on the constant, so cannot be perfect square trinomials.

The first selection has a middle term that is -ab, not -2ab, so it is not a perfect square trinomial, either.

The second selection is the correct one:

... 4a² -20a +25 = (2a +5)²

4 0

3 years ago

Pliz help...............

katrin [286]

Answer:

Step-by-step explanation: so 7 out of 20 .35 right

and that as a percent is 35%

8 0

3 years ago

Answer qn in attachment

leva [86]

Answer:

$\implies \dfrac{ -4x+7}{2(x-2) }$

Step-by-step explanation:

The given expression to us is ,

$\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}$

Now take the LCM as ( x - 1 ) and Simplify , we have ,

$\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}$

Simplifying further , we get ,

$\implies \dfrac{ -4x+7}{2(x-2) }$

Hence the second option is correct .

4 0

3 years ago

Solve for W in A = 2(L + W)

Roman55 [17]

$\Large\begin{aligned}\\\\&A = 2(L + W)\\&A = 2L+2W\\&2W=A-2L\\&W=\dfrac{A-2L}{2}\end$

4 0

2 years ago

A random experiment was conducted where a Person A tossed five coins and recorded the number of ""heads"". Person B rolled two d

cestrela7 [59]

Answer:

(10) Person B

(11) Person B

(12) $P(5\ or\ 6) = 60\%$

(13) Person B

Step-by-step explanation:

Given

Person A $\to$ 5 coins (records the outcome of Heads)

Person $\to$ Rolls 2 dice (recorded the larger number)

Person A

First, we list out the sample space of roll of 5 coins (It is too long, so I added it as an attachment)

Next, we list out all number of heads in each roll (sorted)

$Head = \{5,4,4,4,4,4,3,3,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2,2,2,1,1,1,1,1,0\}$

$n(Head) = 32$

Person B

First, we list out the sample space of toss of 2 coins (It is too long, so I added it as an attachment)

Next, we list out the highest in each toss (sorted)

$Dice = \{2,2,3,3,3,3,4,4,4,4,4,4,5,5,5,5,5,5,5,5,6,6,6,6,6,6,6,6,6,6\}$

$n(Dice) = 30$

Question 10: Who is likely to get number 5

From person A list of outcomes, the proportion of 5 is:

$Pr(5) = \frac{n(5)}{n(Head)}$

$Pr(5) = \frac{1}{32}$

$Pr(5) = 0.03125$

From person B list of outcomes, the proportion of 5 is:

$Pr(5) = \frac{n(5)}{n(Dice)}$

$Pr(5) = \frac{8}{30}$

$Pr(5) = 0.267$

<em>From the above calculations: </em> $0.267 > 0.03125$ <em> Hence, person B is more likely to get 5</em>

Question 11: Person with Higher median

For person A

$Median = \frac{n(Head) + 1}{2}th$

$Median = \frac{32 + 1}{2}th$

$Median = \frac{33}{2}th$

$Median = 16.5th$

This means that the median is the mean of the 16th and the 17th item

So,

$Median = \frac{3+2}{2}$

$Median = \frac{5}{2}$

$Median = 2.5$

For person B

$Median = \frac{n(Dice) + 1}{2}th$

$Median = \frac{30 + 1}{2}th$

$Median = \frac{31}{2}th$

$Median = 15.5th$

This means that the median is the mean of the 15th and the 16th item. So,

$Median = \frac{5+5}{2}$

$Median = \frac{10}{2}$

$Median = 5$

<em>Person B has a greater median of 5</em>

Question 12: Probability that B gets 5 or 6

This is calculated as:

$P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}$

From the sample space of person B, we have:

$n(5\ or\ 6) =n(5) + n(6)$

$n(5\ or\ 6) =8+10$

$n(5\ or\ 6) = 18$

So, we have:

$P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}$

$P(5\ or\ 6) = \frac{18}{30}$

$P(5\ or\ 6) = 0.60$

$P(5\ or\ 6) = 60\%$

Question 13: Person with higher probability of 3 or more

Person A

$n(3\ or\ more) = 16$

So:

$P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Head)}$

$P(3\ or\ more) = \frac{16}{32}$

$P(3\ or\ more) = 0.50$

$P(3\ or\ more) = 50\%$

Person B

$n(3\ or\ more) = 28$

So:

$P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Dice)}$

$P(3\ or\ more) = \frac{28}{30}$

$P(3\ or\ more) = 0.933$

$P(3\ or\ more) = 93.3\%$

By comparison:

$93.3\% > 50\%$

Hence, person B has a higher probability of 3 or more

7 0

3 years ago