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never [62]
3 years ago
10

Something I should look for when trying to decide if a source is credible is the publication's ....

Computers and Technology
1 answer:
storchak [24]3 years ago
7 0
Answer: Date

Explanation: We receive new information everyday, and things are always changing. If something is old, it may need to be updated with the correct information
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When spraying pesticide wear and protective eyeglass​
exis [7]
Ummmmmmmmmmmmmmmmmmmmm ok
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2 years ago
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Take the average of some numbers. Show all the numbers that are below average. You can assume that there will not be more than 2
olchik [2.2K]

Here is code in java.

import java.util.*; // import package

class Main //  creating class

{

public static void main (String[] args) // main method

{

Scanner br=new Scanner(System.in); // scanner class for input

       int []a=new int[20]; // declaring array

       int count=0,x,j; // creating variable

       int sum =0;

       System.out.println("Enter a weight (0 to stop):");

       x=br.nextInt(); // taking input

while(x!=0) // iterating over the loop

       {

           a[count] = x;

           count++;

           System.out.println("Enter a weight (0 to stop):");

           x=br.nextInt();

}

       for( j=0;j<count;j++) // iterating over the loop

       {

       sum+=a[j];

       }

       double avg = sum/(double)count;

       System.out.println("The total is: "+sum);

       System.out.println("The average is: "+avg);

       System.out.println("Here are all the numbers less than the average: ");

     for( j=0;j<count;j++) //  // iterating over the loop

       {

           if(a[j]<avg)

           System.out.print(a[j]+" ");

       }

}

}

Explanation:

First create an object of "Scanner" class to read input from the user.

Create an array of size 20, which store the number given by user.Ask user

to give input and keep the count of number in the variable "count". If user

give input 0 then it will stop taking input.And then calculate sum of all the

input.It will calculate average by dividing the sum with count and print it.

It will compare the all elements of array with average value, if the element

is less than average, it will print that element.

Output:

Enter a weight (0 to stop):

1

Enter a weight (0 to stop):

2

Enter a weight (0 to stop):

3

Enter a weight (0 to stop):

4

Enter a weight (0 to stop):

5

Enter a weight (0 to stop):

6

Enter a weight (0 to stop):

7

Enter a weight (0 to stop):

8

Enter a weight (0 to stop):

9

Enter a weight (0 to stop):

10

Enter a weight (0 to stop):

0

The total is: 55

The average is: 5.5

Here are all the numbers less than the average:

1 2 3 4 5

6 0
3 years ago
Nowadays computer games are mostly available on external<br> hard disk.<br> Is it true or false?
sergey [27]

Answer:

false

Explanation:

because a lot of times they are downloads without the disk

7 0
3 years ago
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10 points if right...
aivan3 [116]

email because with chat it might wake up the kids and wbsite doesnt make sense. neither does blog so with email you can give personal messages and pictures.

7 0
3 years ago
Read 2 more answers
JAVA
avanturin [10]

Answer:

   public ArrayList onlyBlue(String[] clothes){

       ArrayList<String> blueCloths = new ArrayList<>();

       for(int i =0; i<clothes.length; i++){

           if(clothes[i].equalsIgnoreCase("blue")){

               blueCloths.add(clothes[i]);

           }

       }

       return blueCloths;

   }

Explanation:

  • Create the method to accept an Array object of type String representing colors with a return type of an ArrayList
  • Within the method body, create and initialize an Arraylist
  • Use a for loop to iterate the Array of cloths.
  • Use an if statement within the for loop to check if item equals blue and add to the Arraylist.
  • Finally return the arrayList to the caller
3 0
3 years ago
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