Answer:
6(2x + 3y)
Step-by-step explanation:
6 × 2x + 6 × 3y
6(2x + 3y)
You would need 3 cups of flour because 1*2 is 2 and 2*3 is 6 and 6 divided by 2 is 3
Hi there!
![3 \sqrt{54} + 2 \sqrt{24} =](https://tex.z-dn.net/?f=3%20%5Csqrt%7B54%7D%20%2B%202%20%5Csqrt%7B24%7D%20%3D%20)
First we split up the square root into two parts.
![3 \times \sqrt{9} \times \sqrt{6} + 2 \times \sqrt{4} \times \sqrt{6} =](https://tex.z-dn.net/?f=3%20%5Ctimes%20%5Csqrt%7B9%7D%20%5Ctimes%20%5Csqrt%7B6%7D%20%2B%202%20%5Ctimes%20%5Csqrt%7B4%7D%20%5Ctimes%20%5Csqrt%7B6%7D%20%3D%20)
Now we calculate the value of the square roots which have an integer as a solution
![3 \times 3 \times \sqrt{6} + 2 \times 2 \times \sqrt{6} =](https://tex.z-dn.net/?f=3%20%5Ctimes%203%20%5Ctimes%20%5Csqrt%7B6%7D%20%2B%202%20%5Ctimes%202%20%5Ctimes%20%5Csqrt%7B6%7D%20%3D%20)
Multiplying the integers gives us our next step.
![9 \sqrt{6} + 4 \sqrt{6} =](https://tex.z-dn.net/?f=9%20%5Csqrt%7B6%7D%20%2B%204%20%5Csqrt%7B6%7D%20%3D%20)
And finally we add up the roots.
Answer:
33/10 and 55/15
Step-by-step explanation:
Possible denominators that are multiples of 5 less than 17 are 5, 10, 15.
Corresponding numerator ranges are [15, 20], [30, 40], and [45, 60]. In only two of these ranges are there any multiples of 11.
33 in [30, 40]
55 in [45, 60]
So, there are only two possible fractions meeting your requirement:
33/10 and 55/15
The answer for ure question is x<-1/2
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