All categories

3 years ago

HELP ME PLZZ NEED HELP

Mathematics

2 answers:

Anastaziya [24]3 years ago

8 0

Answer:

40%

Step-by-step explanation:

Total amount of marbles are 25

the chances of getting green marbles out of all the marbles are 10/25 or 0.4

and since we are looking for percentages we have to multiply 0.4 by 100

0.4 x 100 = 40

liraira [26]3 years ago

6 0

Step-by-step explanation:

$Given \: \\ Total \: number \: of \: marbles \: \\ = 6 + 9 + 10 = 25 \\ So \: P(Getting \: a \: green \: marble) \\ = \frac{Number \: of \: green \: marbles }{Total \: number \: of \: marbles} = \frac{10}{25}$

$\frac{10}{25} as \: a \: percentage \\ ( \: 40\% \: )$

hOpE iT hElPs YoU

<h3>I nEEd bRainLIeST pLz</h3>

You might be interested in

Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2

Vsevolod [243]

Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

if a , a+ commutator, it obeys $aa^+ = a^+a$

First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

Now;

$a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

therefore, $aa^+ = a^+a$ which implies the operators a and a+ are commutators.

7 0

3 years ago

Determine all solutions of the equation x^y+y = y^x + x in a set of natural numbers.

kodGreya [7K]

Answer:

sum

Step-by-step explanation:

6 0

3 years ago

Write an equation for a line with a slope of -2, and a y-intercept of 1.

Kaylis [27]

Answer:

y = -2x + 1

Step-by-step explanation:

y = mx+b

m = slope

b = y intecept

plug in slop and y intercept

4 0

3 years ago

Read 2 more answers

The volume of fuel in a tank changes at a rate given by the equation V'\left(t\right)=\frac{4t}{\sqrt[3]{t^2+3}},\:t\ge0 V ′ ( t

Ksju [112]

$V'(t)=\dfrac{4t}{\sqrt[3]{t^2+3}}$

The volume of fuel in the tank after 9 hours is given by

$\displaystyle\int_0^9V'(t)\,\mathrm dt=\int_0^9\dfrac{4t}{(t^2+3)^{1/3}}\,\mathrm dt$

To compute the integral, substitute $u=t^2+3$ , so that $\mathrm du=2t\,\mathrm dt$ . Then when $t=0$ , $u=0^2+3=3$ ; when $t=9$ , $u=9^2+3=84$ .

$\displaystyle\int_0^9V'(t)\,\mathrm dt=2\int_{t=0}^{t=9}\frac{2t}{(t^2+3)^{1/3}}\,\mathrm dt=2\int_{u=3}^{u=84}u^{-1/3}\,\mathrm du$
$=2\cdot\dfrac32u^{2/3}\bigg|_{u=3}^{u=84}=3(84^{2/3}-3^{2/3})\approx51.3$

So the volume of fuel after 9 hours is about 51.3 gallons.

8 0

4 years ago

A major application of analytics in marketing is determining customer retention. Suppose that the probability of a long-distance

Marianna [84]

Hey! How are you? My name is Maria, 19 years old. Yesterday broke up with a guy, looking for casual sex.

Write me here and I will give you my phone number - *pofsex.com*

My nickname - Lovely

7 0

3 years ago